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Chemical Equations Balanced on 12/03/06

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

BaCl2 + AgNO3 = Ba(NO3)2 + AgCl =>
BaCl2 + 2 AgNO3 = Ba(NO3)2 + 2 AgCl

K3N = K + N2 =>
2 K3N = 6 K + N2

Al2(SO4)3 + Ca(OH)2 = Al(OH)3 + CaSO4 =>
Al2(SO4)3 + 3 Ca(OH)2 = 2 Al(OH)3 + 3 CaSO4

Bi + Br2 = BiBr3 =>
2 Bi + 3 Br2 = 2 BiBr3

C6H12O6 + O2 = CO2 + H2O =>
C6H12O6 + 6 O2 = 6 CO2 + 6 H2O

Ca(OH)2 + HNO3 = Ca(NO3)2 + HOH =>
Ca(OH)2 + 2 HNO3 = Ca(NO3)2 + 2 HOH

Ni(NO3)2 + NaHCO3 = Ni(HCO3)2 + Na2(NO3)2 =>
Ni(NO3)2 + 2 NaHCO3 = Ni(HCO3)2 + Na2(NO3)2

Ni(NO3)2 + NaHCO3 = Ni(HCO3)2 + Na2(NO3)2 =>
Ni(NO3)2 + 2 NaHCO3 = Ni(HCO3)2 + Na2(NO3)2

Ni(NO3)2 + NaHCO3 = Ni(HCO3)2 + Na2(NO3)2 =>
Ni(NO3)2 + 2 NaHCO3 = Ni(HCO3)2 + Na2(NO3)2

Ni(NO3)2 + NaHCO3 = Ni(HCO3)2 + Na2(NO3)2 =>
Ni(NO3)2 + 2 NaHCO3 = Ni(HCO3)2 + Na2(NO3)2

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

Ni(NO3)2 + K3Fe(CN)6 = Ni3Fe(CN)6 + K(NO3)2 =>
3 Ni(NO3)2 + K3Fe(CN)6 = Ni3Fe(CN)6 + 3 K(NO3)2

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

NaHCO3 + HC2H3O2 = NaC2H3O2 + H2O + CO2 =>
NaHCO3 + HC2H3O2 = NaC2H3O2 + H2O + CO2

Cu(NO3)2 + Na3PO4 = Cu3(PO4)2 + Na3(NO3)3 =>
3 Cu(NO3)2 + 2 Na3PO4 = Cu3(PO4)2 + 2 Na3(NO3)3

NaHCO3 + HC2H3O2 = NaC2H3O2 + H2O + CO2 =>
NaHCO3 + HC2H3O2 = NaC2H3O2 + H2O + CO2

Cu(NO3)2 + Na3PO4 = Cu3(PO4)2 + Na3(NO3)3 =>
3 Cu(NO3)2 + 2 Na3PO4 = Cu3(PO4)2 + 2 Na3(NO3)3

Cu(NO3)2 + K3Fe(CN)6 = Cu3Fe(CN)6 + K(NO3)2 =>
3 Cu(NO3)2 + K3Fe(CN)6 = Cu3Fe(CN)6 + 3 K(NO3)2

Cu(NO3)2 + K3Fe(CN)6 = Cu3Fe(CN)6 + K(NO3)2 =>
3 Cu(NO3)2 + K3Fe(CN)6 = Cu3Fe(CN)6 + 3 K(NO3)2

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

Hg(NO3)2 + Na3PO4 = Hg3(PO4)2 + Na3(NO3)3 =>
3 Hg(NO3)2 + 2 Na3PO4 = Hg3(PO4)2 + 2 Na3(NO3)3

Hg(NO3)2 + K3Fe(CN)6 = Hg3Fe(CN)6 + K(NO3)2 =>
3 Hg(NO3)2 + K3Fe(CN)6 = Hg3Fe(CN)6 + 3 K(NO3)2

Ba(NO3)2 + Na3PO4 = Ba3(PO4)2 + Na3(NO3)3 =>
3 Ba(NO3)2 + 2 Na3PO4 = Ba3(PO4)2 + 2 Na3(NO3)3

KClO3 + P = KCl + P4O10 =>
10 KClO3 + 12 P = 10 KCl + 3 P4O10

Ba(NO3)2 + K3Fe(CN)6 = Ba3Fe(CN)6 + K(NO3)2 =>
3 Ba(NO3)2 + K3Fe(CN)6 = Ba3Fe(CN)6 + 3 K(NO3)2

Pb(NO3)2 + Na3PO4 = Pb3(PO4)2 + Na3(NO3)3 =>
3 Pb(NO3)2 + 2 Na3PO4 = Pb3(PO4)2 + 2 Na3(NO3)3

Pb(NO3)2 + K3Fe(CN)6 = Pb3Fe(CN)6 + K(NO3)2 =>
3 Pb(NO3)2 + K3Fe(CN)6 = Pb3Fe(CN)6 + 3 K(NO3)2

KI + H2SO4 = K2SO4 + I2 + H2S + H2O =>
8 KI + 5 H2SO4 = 4 K2SO4 + 4 I2 + H2S + 4 H2O

KBr + H2SO4 = K2SO4 + Br2 + SO2 + H2O =>
2 KBr + 2 H2SO4 = K2SO4 + Br2 + SO2 + 2 H2O

KBr + H2SO4 = K2SO4 + Br2 + SO2 + H2O =>
2 KBr + 2 H2SO4 = K2SO4 + Br2 + SO2 + 2 H2O

Ca3(PO4)2 + SiO2 + C = CaSiO3 + P4 + CO =>
2 Ca3(PO4)2 + 6 SiO2 + 10 C = 6 CaSiO3 + P4 + 10 CO

Fe(III)NO3 + LiOH2 = LiNO3 + Fe(III)OH2 =>
Fe(III)NO3 + LiOH2 = LiNO3 + Fe(III)OH2

TiO2 + NaCl = Ti(Cl) + Na(O)2 =>
TiO2 + NaCl = Ti(Cl) + Na(O)2

FeCl3 + K(OH) = Fe(OH)3 + KCl =>
FeCl3 + 3 K(OH) = Fe(OH)3 + 3 KCl

Ba(NO3)2 + K2CrO7 = BaCrO7 + K(NO3) =>
Ba(NO3)2 + K2CrO7 = BaCrO7 + 2 K(NO3)

Al2(SO4)3 + BaCl2 = AlCl3 + Ba(SO4) =>
Al2(SO4)3 + 3 BaCl2 = 2 AlCl3 + 3 Ba(SO4)

Pb(NO3)2 + KI = PbI2 + KNO3 =>
Pb(NO3)2 + 2 KI = PbI2 + 2 KNO3

Cr(NCS)6{4-} + Ce{4+} + H2O = Cr{3+} + Ce{3+} + NO{3-} + CO2 + SO4{2-} + H{+} =>
Cr(NCS)6{4-} + 61 Ce{4+} + 42 H2O = Cr{3+} + 61 Ce{3+} + 6 NO{3-} + 6 CO2 + 6 SO4{2-} + 84 H{+}

Cr(NCS)6{4-} + Ce{4+} + H2O = Cr{3+} + Ce{3+} + NO3{-} + CO2 + SO4{2-} + H{+} =>
Cr(NCS)6{4-} + 97 Ce{4+} + 54 H2O = Cr{3+} + 97 Ce{3+} + 6 NO3{-} + 6 CO2 + 6 SO4{2-} + 108 H{+}

CrI3 + Cl2 + OH{-} = CrO4{2-} + IO4{-} + Cl{-} + H2O =>
2 CrI3 + 27 Cl2 + 64 OH{-} = 2 CrO4{2-} + 6 IO4{-} + 54 Cl{-} + 32 H2O

Fe(CN)6{4-} + Ce{4+} + OH{-} = Ce(OH)3 + Fe(OH)3 + CO3{2-} + NO3{-} + H2O =>
Fe(CN)6{4-} + 61 Ce{4+} + 258 OH{-} = 61 Ce(OH)3 + Fe(OH)3 + 6 CO3{2-} + 6 NO3{-} + 36 H2O

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Balance equation of any chemical reaction online for free
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 11/26/06
Equations balanced on 11/03/06

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