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Chemical Equations Balanced on 06/07/12

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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SO2(g) + H2O(l) = H2SO3(aq) =>
SO2(g) + H2O(l) = H2SO3(aq)

SO2(g) + H2O(l) = H2SO3(aq) =>
SO2(g) + H2O(l) = H2SO3(aq)

PbO2 + HCl = PbCl2 + Cl2 + H2O =>
PbO2 + 4 HCl = PbCl2 + Cl2 + 2 H2O

H2O = H2O =>
H2O = H2O

KHCO3 = K2CO3 + CO2 + H2O =>
2 KHCO3 = K2CO3 + CO2 + H2O

MnO(OH)2 + KI + H2SO4 = Mn(SO4) + K2(SO4) + I2 + H2O =>
MnO(OH)2 + 2 KI + 2 H2SO4 = Mn(SO4) + K2(SO4) + I2 + 3 H2O

B2H6 = B5H9 + H2 =>
5 B2H6 = 2 B5H9 + 6 H2

MnO(OH)2 + KI + H2SO4 = Mn(SO4) + K2(SO4) + I2 + H2O =>
MnO(OH)2 + 2 KI + 2 H2SO4 = Mn(SO4) + K2(SO4) + I2 + 3 H2O

MgSO4(aq) + PB(CH3COO)2(aq) = Mg(CH3COO)2(aq) + PBSO4(s) =>
MgSO4(aq) + PB(CH3COO)2(aq) = Mg(CH3COO)2(aq) + PBSO4(s)

AgNO3 + NaCl = AgCl + NaNO3 =>
AgNO3 + NaCl = AgCl + NaNO3

AgNO3 + NaCl = AgCl + NaNO3 =>
AgNO3 + NaCl = AgCl + NaNO3

K2Cr2O7 + H2SO4 + H2O2 = CrO5 + K2SO4 + H2O =>
K2Cr2O7 + H2SO4 + 4 H2O2 = 2 CrO5 + K2SO4 + 5 H2O

CO2 + Ca(OH)2 = CaCO3 + H2O =>
CO2 + Ca(OH)2 = CaCO3 + H2O

K2Cr2O7 + H2SO4 + H2O2 = H2Cr2O12 + K2SO4 + H2O =>
K2Cr2O7 + H2SO4 + 5 H2O2 = H2Cr2O12 + K2SO4 + 5 H2O

Ca + H2O = Ca(OH)2 + H2 =>
Ca + 2 H2O = Ca(OH)2 + H2

Fe2O3 + H2SO4 = Fe2(SO4)3 + H2O =>
Fe2O3 + 3 H2SO4 = Fe2(SO4)3 + 3 H2O

CrO5 + H2SO4 + KI = I2 + Cr2(SO4)3 + K2SO4 + H2O =>
2 CrO5 + 10 H2SO4 + 14 KI = 7 I2 + Cr2(SO4)3 + 7 K2SO4 + 10 H2O

NH3 + CO2 + H2O = (NH4)2CO3 =>
2 NH3 + CO2 + H2O = (NH4)2CO3

Hg2Cl2 + SO2 + HCl = HgCl2 + H2O + S =>
2 Hg2Cl2 + SO2 + 4 HCl = 4 HgCl2 + 2 H2O + S

AgNO + NaCl = AgCl + NaNO =>
AgNO + NaCl = AgCl + NaNO

AgNO + NaCl = AgCl + NaNO =>
AgNO + NaCl = AgCl + NaNO

CoSO4 + H3PO4 = Co3(PO4)2 + H2SO4 =>
3 CoSO4 + 2 H3PO4 = Co3(PO4)2 + 3 H2SO4

B5H9 + K2Cr2O7 + H2SO4 = B(OH)3 + Cr2(SO4)3 + K2SO4 + H2O =>
B5H9 + 4 K2Cr2O7 + 16 H2SO4 = 5 B(OH)3 + 4 Cr2(SO4)3 + 4 K2SO4 + 13 H2O

P + NH4ClO4 + H2O = H3PO4 + NH3 + Cl2 =>
14 P + 10 NH4ClO4 + 16 H2O = 14 H3PO4 + 10 NH3 + 5 Cl2

HNO3 + Fe = Fe(NO3)3 + H2O + NO2 =>
6 HNO3 + Fe = Fe(NO3)3 + 3 H2O + 3 NO2

CH3CH3 + O2 = CO2 + H2O =>
2 CH3CH3 + 7 O2 = 4 CO2 + 6 H2O

NaOH + Na2SO4 = NaSO4 + Na2OH =>
NaOH + Na2SO4 = NaSO4 + Na2OH

H2Cr2O12 + H2SO4 + KI = I2 + Cr2(SO4)3 + K2SO4 + H2O =>
H2Cr2O12 + 11 H2SO4 + 16 KI = 8 I2 + Cr2(SO4)3 + 8 K2SO4 + 12 H2O

KMnO4 + FeSo4 = KMnSo4 + FeO4 =>
KMnO4 + FeSo4 = KMnSo4 + FeO4

PbO3 = PbO + O2 =>
PbO3 = PbO + O2

K2Cu(SO4)2 + BaCl2 = BaSO4 + KCl + CuCl2 =>
K2Cu(SO4)2 + 2 BaCl2 = 2 BaSO4 + 2 KCl + CuCl2

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

K2Cu(SO4)2 + H2O = KOH + Cu(OH)2 + H2SO4 =>
K2Cu(SO4)2 + 4 H2O = 2 KOH + Cu(OH)2 + 2 H2SO4

P4 + O2 = P2O5 =>
P4 + 5 O2 = 2 P2O5

MnSO4 + PbO2 + HNO3 = Pb(MnO4)2 + PbSO4 + Pb(NO3)2 + H2O =>
2 MnSO4 + 5 PbO2 + 4 HNO3 = Pb(MnO4)2 + 2 PbSO4 + 2 Pb(NO3)2 + 2 H2O

B(OH)3 + KOH = K2[B5O8(OH)]*2H2O + H2O =>
5 B(OH)3 + 2 KOH = K2[B5O8(OH)]*2H2O + 6 H2O

KAl(SO4)2 + H2O = KOH + Al(OH)3 + H2SO4 =>
KAl(SO4)2 + 4 H2O = KOH + Al(OH)3 + 2 H2SO4

NaOH + H2SO4 = Na2SO4 + H2O =>
2 NaOH + H2SO4 = Na2SO4 + 2 H2O

K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO

KAl(SO4)2 + NH4OH = KOH + Al(OH)3 + (NH4)2SO4 =>
KAl(SO4)2 + 4 NH4OH = KOH + Al(OH)3 + 2(NH4)2SO4

KAl(SO4)2 + BaCl2 = BaSO4 + KCl + AlCl3 =>
KAl(SO4)2 + 2 BaCl2 = 2 BaSO4 + KCl + AlCl3

PbS + H2O2 = PbSO4 + H2O =>
PbS + 4 H2O2 = PbSO4 + 4 H2O

KBr + H2SO4 + H2O2 = Br + K2SO4 + H2O =>
2 KBr + H2SO4 + H2O2 = 2 Br + K2SO4 + 2 H2O

BaCl(aq) + Li2Cr(aq) = BaCr(s) + Li2Cl(aq) =>
BaCl(aq) + Li2Cr(aq) = BaCr(s) + Li2Cl(aq)

BaCl(aq) + Li2Cr(aq) = BaCr(s) + Li2Cl(aq) =>
BaCl(aq) + Li2Cr(aq) = BaCr(s) + Li2Cl(aq)

KMnO4 + HCl = KCl + MnCl2 + Cl2 + H2O =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 5 Cl2 + 8 H2O

NaOH + ZnSO4 = NaSO4 + ZnOH =>
NaOH + ZnSO4 = NaSO4 + ZnOH

C2H4 + O2 = CO2 + H2O =>
C2H4 + 3 O2 = 2 CO2 + 2 H2O

Cl2 + Fe = FeCl3 =>
3 Cl2 + 2 Fe = 2 FeCl3

C2H4 + O2 = CO2 + H2O =>
C2H4 + 3 O2 = 2 CO2 + 2 H2O

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Balance equation of any chemical reaction online for free
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