Equations balanced on the previous day | Equations balanced on the next day |
8 Al3(SO)4 + 7(NH4)2S + 68 H2O = 24 Al(OH)3 + 32 H2S + 7(NH4)2SO4
Mg3(PO4)2 + BaF2 = MgF2 + Ba3(PO4)2 =>
Mg3(PO4)2 + 3 BaF2 = 3 MgF2 + Ba3(PO4)2
AlCu2 + Cl = AlCl + Cu =>
AlCu2 + Cl = AlCl + 2 Cu
Mn + NiCl2 = MnCl3 + Ni =>
2 Mn + 3 NiCl2 = 2 MnCl3 + 3 Ni
Cu(NO3)2 + NaOH = Cu(OH)2 + NaNO3 =>
Cu(NO3)2 + 2 NaOH = Cu(OH)2 + 2 NaNO3
HCHO2 + NaOH = H2O + CHO2Na =>
HCHO2 + NaOH = H2O + CHO2Na
Ca(HCO3)2 + HNO3(dil) = Ca(NO3)2 + CO2 + H2O =>
Ca(HCO3)2 + 2 HNO3(dil) = Ca(NO3)2 + 2 CO2 + 2 H2O
Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2
HCl + H2O = H3O{+} + Cl{-} =>
HCl + H2O = H3O{+} + Cl{-}
Cu + H2SO4 = CuSO4 + H2O + SO2 =>
Cu + 2 H2SO4 = CuSO4 + 2 H2O + SO2
AgNo3(aq) + Na3Po4(aq) = Ag3Po4(s) + NaNo3(aq) =>
3 AgNo3(aq) + Na3Po4(aq) = Ag3Po4(s) + 3 NaNo3(aq)
N3H + H2O = N3 + H3O =>
N3H + H2O = N3 + H3O
NaI + NaBr + C4H10O + HCl + NaClO = H2O + BrICl2O + C4H9Na3 =>
NaI + NaBr + C4H10O + HCl + NaClO = H2O + BrICl2O + C4H9Na3
Si + HNO3 = Si(NO3)2 + H2 =>
Si + 2 HNO3 = Si(NO3)2 + H2
C4H8N2O2 + H2O2 + H2SO4 = (NH4)2SO4 + CO2 + H2O =>
C4H8N2O2 + 7 H2O2 + H2SO4 = (NH4)2SO4 + 4 CO2 + 8 H2O
KBiO3 + K2SO3 + H2SO4 = Bi2(SO4)3 + K2SO4 + H2O =>
2 KBiO3 + 2 K2SO3 + 4 H2SO4 = Bi2(SO4)3 + 3 K2SO4 + 4 H2O
Ca3(PO4)2 + H2SO4 = CaSO4 + Ca(H2PO4)2 =>
Ca3(PO4)2 + 2 H2SO4 = 2 CaSO4 + Ca(H2PO4)2
Fe2O3 + SO2 = Fe2O3SO2 =>
Fe2O3 + SO2 = Fe2O3SO2
Br2 + AlCl3 = Al3 + Br2Cl =>
9 Br2 + 3 AlCl3 = Al3 + 9 Br2Cl
[SnCl6] + H2 = H2[SnCl6] =>
[SnCl6] + H2 = H2[SnCl6]
CH3COOAg + K2Cr2O7 = Ag2Cr2O7 + CH3COOK =>
2 CH3COOAg + K2Cr2O7 = Ag2Cr2O7 + 2 CH3COOK
HXeO4 + Ni(OH)2 = Xe + NiO2 + H2O =>
2 HXeO4 + 7 Ni(OH)2 = 2 Xe + 7 NiO2 + 8 H2O
Pb[NO3]2 + NaI = PbI2 + NaNO3 =>
Pb[NO3]2 + 2 NaI = PbI2 + 2 NaNO3
Fe{+3} + CO = Fe + CO{+2) =>
2 Fe{+3} + 3 CO = 2 Fe + 3 CO{+2)
FeO + H2O = Fe(HO)2 =>
FeO + H2O = Fe(HO)2
Na3(PO4) + Ca(NO3)2 = NaNO3 + Ca3(PO4)2 =>
2 Na3(PO4) + 3 Ca(NO3)2 = 6 NaNO3 + Ca3(PO4)2
S2O4{2-} + CrO4{2-} + OH{-} + H2O = Cr(OH)3 + SO3{2-} =>
3 S2O4{2-} + 2 CrO4{2-} + 2 OH{-} + 2 H2O = 2 Cr(OH)3 + 6 SO3{2-}
ZnSO4 + H2S + H2O = Zn + H2SO4 =>
4 ZnSO4 + H2S + 4 H2O = 4 Zn + 5 H2SO4
Fe(OH)3 + HNo3 = Fe(No3)3(aq) + H2O(l) =>
Fe(OH)3 + 3 HNo3 = Fe(No3)3(aq) + 3 H2O(l)
Ba(CH3COO)2 = Ba + (CH3COO)2 =>
Ba(CH3COO)2 = Ba + (CH3COO)2
CaOH + HC2H3O2 = HCa + C2H3O2OH =>
CaOH + HC2H3O2 = HCa + C2H3O2OH
Zn + NH4HCO3 + H2O = NH4Zn(OH)4 + H2 + CO2 =>
2 Zn + 2 NH4HCO3 + 6 H2O = 2 NH4Zn(OH)4 + 3 H2 + 2 CO2
NaNO3 + As + NaOH = Na3AsO4 + NH3 + H2O =>
5 NaNO3 + 8 As + 19 NaOH = 8 Na3AsO4 + 5 NH3 + 2 H2O
(NH4)2CO3 + K2SO4 = (NH4)2SO4 + K2CO3 =>
(NH4)2CO3 + K2SO4 = (NH4)2SO4 + K2CO3
N2H2 + H2O2 = N2 + H2O =>
N2H2 + H2O2 = N2 + 2 H2O
CO2 + KOH = H2O + K2CO3 =>
CO2 + 2 KOH = H2O + K2CO3
Al(OH)3 + Sr = Sr(OH)2 + Al =>
2 Al(OH)3 + 3 Sr = 3 Sr(OH)2 + 2 Al
NH3 + Cl2 = NCl3 + HCl =>
NH3 + 3 Cl2 = NCl3 + 3 HCl
Cu(CH3COO)2 + Na3PO4 = Cu3(PO4)2 + Na2(CH3COO)2 =>
3 Cu(CH3COO)2 + 2 Na3PO4 = Cu3(PO4)2 + 3 Na2(CH3COO)2
Co(NO3)2 + Li2CO3 = Co(CO3)2 + Li2NO3 =>
Co(NO3)2 + 2 Li2CO3 = Co(CO3)2 + 2 Li2NO3
H{+} + ZnS + NO3{-} = Zn{+} + S + NO + H2O =>
4 H{+} + 3 ZnS + NO3{-} = 3 Zn{+} + 3 S + NO + 2 H2O
C + H2 = CH4 =>
C + 2 H2 = CH4
Mg(NO3)2 + NH4Cl + Na2HPO4 + NH4OH = MgNH4PO4 + NaCl + NH4(NO3) + H2O =>
Mg(NO3)2 + 2 NH4Cl + Na2HPO4 + NH4OH = MgNH4PO4 + 2 NaCl + 2 NH4(NO3) + H2O
OH + C = CH4 + O2 =>
4 OH + C = CH4 + 2 O2
Ba(NO3)2 + CoSO4 = BaSO4 + Co(NO3)2 =>
Ba(NO3)2 + CoSO4 = BaSO4 + Co(NO3)2
C7H8 + C5H11Cl = C11H16 + HCl =>
5 C7H8 + 4 C5H11Cl = 5 C11H16 + 4 HCl
FeSO + KMnO + H2SO4 = Fe(SO4)3 + KHSO + MnSO4 + H2O =>
FeSO + 2 KMnO + 6 H2SO4 = Fe(SO4)3 + 2 KHSO + 2 MnSO4 + 5 H2O
H2O + K3N + KMnO4 = N2 + KOH + MnO2 =>
4 H2O + 2 K3N + 2 KMnO4 = N2 + 8 KOH + 2 MnO2
HCl(l) + Fe(s) + O2(g) = FeCl2 + H2O =>
4 HCl(l) + 2 Fe(s) + O2(g) = 2 FeCl2 + 2 H2O
K2O2 + KJ + H2SO4 = J2 + K2SO4 + H2O =>
K2O2 + 2 KJ + 2 H2SO4 = J2 + 2 K2SO4 + 2 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/08/23
Equations balanced on 01/07/23
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