Equations balanced on the previous day | Equations balanced on the next day |
2 CH3COONa + (NH4)2SO4 = Na2SO4 + 2 NH4CH3COO
U + H2SO4 = U(SO4)2 + H2 =>
U + 2 H2SO4 = U(SO4)2 + 2 H2
HCl + Zn = ClZnCl + HH =>
2 HCl + Zn = ClZnCl + HH
Fe(OH)3 + H2 = Fe(OH)2 + H2O =>
2 Fe(OH)3 + H2 = 2 Fe(OH)2 + 2 H2O
Ba(aq) + H2SO4(aq) = BaSO4(s) + H2(aq) =>
Ba(aq) + H2SO4(aq) = BaSO4(s) + H2(aq)
Ca(AsO4)2 + HCl = CaCl + AsO3 + HO2 =>
Ca(AsO4)2 + HCl = CaCl + 2 AsO3 + HO2
CrO + Br2 + H2O = HBr + Cr(OH)3 =>
2 CrO + Br2 + 4 H2O = 2 HBr + 2 Cr(OH)3
SBCl5 + KI = KCl + I2 + SBCl3 =>
SBCl5 + 2 KI = 2 KCl + I2 + SBCl3
AlOH3 + KBr = AlBr + KOH3 =>
AlOH3 + KBr = AlBr + KOH3
CuOHCl + NH4Cl + NH4OH = [Cu(NH3)4]Cl2 + H2O =>
CuOHCl + NH4Cl + 3 NH4OH = [Cu(NH3)4]Cl2 + 4 H2O
Au3 + S2 = AuS =>
2 Au3 + 3 S2 = 6 AuS
(NH4)2C2O4 + KMnO4 + H2SO4 = MnSO4 + (NH4)2SO4 + K2SO4 + CO2 + H2O =>
5(NH4)2C2O4 + 2 KMnO4 + 8 H2SO4 = 2 MnSO4 + 5(NH4)2SO4 + K2SO4 + 10 CO2 + 8 H2O
Fe4O6 + C = Fe + C3O6 =>
Fe4O6 + 3 C = 4 Fe + C3O6
CrO + Br2 + H2O = HBr + Cr(OH)3 =>
2 CrO + Br2 + 4 H2O = 2 HBr + 2 Cr(OH)3
W(OH)2 + NaOH = H2WO4 + Na + H2O =>
W(OH)2 + 4 NaOH = H2WO4 + 4 Na + 2 H2O
Ba + NaSO4 = BaSO4 + Na =>
Ba + NaSO4 = BaSO4 + Na
Tb3O4 + HCl = TbCl2 + H2O + Cl =>
Tb3O4 + 8 HCl = 3 TbCl2 + 4 H2O + 2 Cl
Co(NO3)2(aq) + NaI(aq) = CoI2 + NaNO3 =>
Co(NO3)2(aq) + 2 NaI(aq) = CoI2 + 2 NaNO3
Na2H3IO6 + HNO3 = NaIO4 + NaNO3 + H2O =>
Na2H3IO6 + HNO3 = NaIO4 + NaNO3 + 2 H2O
NH4Al(SO4)2 + Na2S = Al2S3 + Na2SO4 + (NH4)2SO4 =>
2 NH4Al(SO4)2 + 3 Na2S = Al2S3 + 3 Na2SO4 + (NH4)2SO4
FeS3 = Fe2S3 + S2 =>
4 FeS3 = 2 Fe2S3 + 3 S2
H3C6O7 + NaHCO3 = Na + H2O + CO2 =>
H3C6O7 + 13 NaHCO3 = 13 Na + 8 H2O + 19 CO2
Cu(ClO3)2 + Fe(OH)2 = Cu(OH)2 + Fe(ClO3)2 =>
Cu(ClO3)2 + Fe(OH)2 = Cu(OH)2 + Fe(ClO3)2
H2C3H2O4 + KOH = KC3H2 + CO2 + H2O =>
15 H2C3H2O4 + 8 KOH = 8 KC3H2 + 21 CO2 + 26 H2O
FeCl3 + Hg = FeCl2 + HgCl2 =>
2 FeCl3 + Hg = 2 FeCl2 + HgCl2
Cr2S3 + Mn(NO3)3 + Na2CO3 = NO + CO2 + Na2CrO4 + NaMnO4 + Na2SO4 =>
Cr2S3 + 6 Mn(NO3)3 + 8 Na2CO3 = 18 NO + 8 CO2 + 2 Na2CrO4 + 6 NaMnO4 + 3 Na2SO4
ZnO + NH3 = Zn + H2O + N2 =>
3 ZnO + 2 NH3 = 3 Zn + 3 H2O + N2
Fe(HSO4)3 + Ba(MnO4)2 = Fe(MnO4)3 + Ba(HSO4)2 =>
2 Fe(HSO4)3 + 3 Ba(MnO4)2 = 2 Fe(MnO4)3 + 3 Ba(HSO4)2
KMnO4 + H2C2O4 = K2C2O4 + MnC2O4 + H2O + CO2 =>
2 KMnO4 + 8 H2C2O4 = K2C2O4 + 2 MnC2O4 + 8 H2O + 10 CO2
Mn2O4 + HCl = MnCl2 + H2O + Cl2 =>
Mn2O4 + 8 HCl = 2 MnCl2 + 4 H2O + 2 Cl2
Ba + Hg(NO3)2 = Ba(NO3)2 + Hg =>
Ba + Hg(NO3)2 = Ba(NO3)2 + Hg
NaCO3(s) + CH3COOH(aq) = NaCH3COO(aq) + HCO3(s) =>
NaCO3(s) + CH3COOH(aq) = NaCH3COO(aq) + HCO3(s)
KMnO4(aq) + NaOH(aq) + Na2SO3(aq) = K2MnO4 + Na2MnO4 + Na2SO4 + H2O =>
2 KMnO4(aq) + 2 NaOH(aq) + Na2SO3(aq) = K2MnO4 + Na2MnO4 + Na2SO4 + H2O
Cr2O3 + KClO3 + K2CO3 = K2Cr2O7 + KCl + CO2 =>
Cr2O3 + KClO3 + K2CO3 = K2Cr2O7 + KCl + CO2
NH3 + CuO = Cu2 + N2 + H2O =>
4 NH3 + 6 CuO = 3 Cu2 + 2 N2 + 6 H2O
Cd(OH)2 + HBr = H2O + CdBr2 =>
Cd(OH)2 + 2 HBr = 2 H2O + CdBr2
Mn7 = Mn4 =>
4 Mn7 = 7 Mn4
NaHSO4 + H3PO4 = Na2HPO4 + H2SO4 =>
2 NaHSO4 + H3PO4 = Na2HPO4 + 2 H2SO4
Na2C2O4 + CuSO4 = Cu(C2O4) + Na2SO4 =>
Na2C2O4 + CuSO4 = Cu(C2O4) + Na2SO4
Zn + H2SO4(merck) = ZnSO4 + H2 =>
Zn + H2SO4(merck) = ZnSO4 + H2
NH3 + CO2 + NaCl + H2O = HNaCO3 + NH4Cl =>
NH3 + CO2 + NaCl + H2O = HNaCO3 + NH4Cl
F5 + FeO = F5O2 + Fe =>
F5 + 2 FeO = F5O2 + 2 Fe
KNO3 + Na = NaO2 + K2O + N2 =>
4 KNO3 + 5 Na = 5 NaO2 + 2 K2O + 2 N2
AsH3 + MnO4 = H2AsO4 + Mn + H2O =>
8 AsH3 + 9 MnO4 = 8 H2AsO4 + 9 Mn + 4 H2O
Cr(OH)3 + H2O2 + (OH){-} = CrO42{-} + H2O =>
Cr(OH)3 + 40 H2O2 + (OH){-} = CrO42{-} + 42 H2O
KMnO4 + FeCl3 + HCl = MnCl2 + FeCl2KCl + Cl2 + H2O =>
KMnO4 + FeCl3 + 8 HCl = MnCl2 + FeCl2KCl + 3 Cl2 + 4 H2O
KMnO4 + H2SO3 = K2 + MnSO4 + H2SO4 + H2O =>
2 KMnO4 + 6 H2SO3 = K2 + 2 MnSO4 + 4 H2SO4 + 2 H2O
CaO + H3PO4 = Ca3(PO4)2 + H(OH) =>
3 CaO + 2 H3PO4 = Ca3(PO4)2 + 3 H(OH)
F2 + NH4OH = NF3 + H2 + O2 =>
3 F2 + 2 NH4OH = 2 NF3 + 5 H2 + O2
NaH + F = NaFH =>
NaH + F = NaFH
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/11/24
Equations balanced on 02/10/23
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