Equations balanced on the previous day | Equations balanced on the next day |
BaCl2 + AgNO3 = Cl2Ag + BaNO3
Pb(NO3)2 + NaBr = PbBr2 + NaNO3 =>
Pb(NO3)2 + 2 NaBr = PbBr2 + 2 NaNO3
Ba(OH)2(aq) + (NH4)2SO4(aq) = BaSO4 + NH4 + OH =>
Ba(OH)2(aq) + (NH4)2SO4(aq) = BaSO4 + 2 NH4 + 2 OH
ClO + H2 = Cl + H2O =>
ClO + H2 = Cl + H2O
K2S + Na2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO4 + Na2SO4 + H2O =>
3 K2S + 4 Na2Cr2O7 + 16 H2SO4 = 4 Cr2(SO4)3 + 3 K2SO4 + 4 Na2SO4 + 16 H2O
PbSO4 = PbSO3 + O2 =>
2 PbSO4 = 2 PbSO3 + O2
CuO(s) + C(s) = Cu(l) + CO(g) =>
CuO(s) + C(s) = Cu(l) + CO(g)
Cl2 + NaOH = NaClO3 + H2O + NaCl =>
3 Cl2 + 6 NaOH = NaClO3 + 3 H2O + 5 NaCl
BaCl2 + AgNO3 = Cl2Ag + BaNO3 =>
BaCl2 + AgNO3 = Cl2Ag + BaNO3
BaCl2(aq) + KBr(aq) = KCl(aq) + BaBr2(s) =>
BaCl2(aq) + 2 KBr(aq) = 2 KCl(aq) + BaBr2(s)
C4H8(OH)2 + H2O2(aq) = C4H6O2(aq) + H2O(l) =>
C4H8(OH)2 + 2 H2O2(aq) = C4H6O2(aq) + 4 H2O(l)
C6H12O6 + CH3OH = C4H8O3 + H2O =>
C6H12O6 + 2 CH3OH = 2 C4H8O3 + 2 H2O
NaNO2 + H2SO4 + NH4OH = NH4NO2 + Na2SO4 + H2O =>
2 NaNO2 + H2SO4 + 2 NH4OH = 2 NH4NO2 + Na2SO4 + 2 H2O
CuSO4 + NaOH = Cu(OH)2 + Na2SO4 =>
CuSO4 + 2 NaOH = Cu(OH)2 + Na2SO4
C2H5O + [Cu(NH3)4](OH)2 = C2H5O2N + Cu2O + NH3 + H2O =>
2 C2H5O + 10[Cu(NH3)4](OH)2 = 2 C2H5O2N + 5 Cu2O + 38 NH3 + 13 H2O
FeOOH + NaHCO3 + H2C2O4*H2O = Na3[Fe(C2O2)] + H2O + CO2 =>
FeOOH + 3 NaHCO3 + 5 H2C2O4*H2O = Na3[Fe(C2O2)] + 12 H2O + 11 CO2
Cl2 + KBr = KCl + Br2 =>
Cl2 + 2 KBr = 2 KCl + Br2
NaOH + Fe2(SO4)3 = Na2SO4 + Fe(OH)3 =>
6 NaOH + Fe2(SO4)3 = 3 Na2SO4 + 2 Fe(OH)3
Zn + NaNO3 + NaOH = Na2ZnO2 + NH3 + H2O =>
4 Zn + NaNO3 + 7 NaOH = 4 Na2ZnO2 + NH3 + 2 H2O
Cr(HSO4)3 + NaOH = [Cr(OH)2]2SO4 + Na2SO4 + H2O =>
2 Cr(HSO4)3 + 10 NaOH = [Cr(OH)2]2SO4 + 5 Na2SO4 + 6 H2O
Zn + NaNO3 + NaOH = Na2ZnO2 + NH3 + H2O =>
4 Zn + NaNO3 + 7 NaOH = 4 Na2ZnO2 + NH3 + 2 H2O
CS2(s) + O2(g) = CO2(g) + S(s) =>
CS2(s) + O2(g) = CO2(g) + 2 S(s)
Ca(OH)2 = CaO + H2O =>
Ca(OH)2 = CaO + H2O
BaCl2(aq) + KBr(aq) = KCl(aq) + BaBr2(s) =>
BaCl2(aq) + 2 KBr(aq) = 2 KCl(aq) + BaBr2(s)
Ca + Fe(NO{3})3 = Ca(NO{3})3 + Fe =>
Ca + Fe(NO{3})3 = Ca(NO{3})3 + Fe
CH3COOK + H2SO4 = CH3COOH + K2SO4 =>
2 CH3COOK + H2SO4 = 2 CH3COOH + K2SO4
Na(SO3) + HI = SO2 + H2O + NaI2 =>
Na(SO3) + 2 HI = SO2 + H2O + NaI2
Cr(OH)3 + NH3 = Cr(NH4)3 + O2 =>
2 Cr(OH)3 + 6 NH3 = 2 Cr(NH4)3 + 3 O2
K2Cr2O7 + Ni(ClO3)2 = KClO3 + NiCr2O7 =>
K2Cr2O7 + Ni(ClO3)2 = 2 KClO3 + NiCr2O7
As2O3 + H2O = H3AsO3 =>
As2O3 + 3 H2O = 2 H3AsO3
FeSO4 + KMnO4 + H2SO4 = KHSO4MnSO4 + Fe2(SO4)3 + H2O =>
10 FeSO4 + 2 KMnO4 + 9 H2SO4 = 2 KHSO4MnSO4 + 5 Fe2(SO4)3 + 8 H2O
NaHCO3 + NaHSO4 = Na2SO4 + CO2 + H2O =>
NaHCO3 + NaHSO4 = Na2SO4 + CO2 + H2O
Cu + BaSO4 = CuSO4 + Ba =>
Cu + BaSO4 = CuSO4 + Ba
CH3COOH + NaHCO3 = CO2 + H2O + NaC2H3CO2 =>
3 CH3COOH + 2 NaHCO3 = 2 CO2 + 4 H2O + 2 NaC2H3CO2
C2H4 + KMnO4 + H2SO4 = H2C2O4 + K2SO4 + MnSO4 + H2O =>
C2H4 + 2 KMnO4 + 3 H2SO4 = H2C2O4 + K2SO4 + 2 MnSO4 + 4 H2O
KClO3 + NiCl2 + HCl = KCl + NiCl3 + H2O =>
KClO3 + 6 NiCl2 + 6 HCl = KCl + 6 NiCl3 + 3 H2O
AgNO3 + BaCl2 = AgCl + Ba(NO3)2 =>
2 AgNO3 + BaCl2 = 2 AgCl + Ba(NO3)2
Zn(s) + AgNO3(aq) = Zn(NO3)2(aq) + Ag(aq) =>
Zn(s) + 2 AgNO3(aq) = Zn(NO3)2(aq) + 2 Ag(aq)
SbO3 + C = Sb + CO3 =>
SbO3 + C = Sb + CO3
Mg + CO2 = MgO + C =>
2 Mg + CO2 = 2 MgO + C
Ca(OH)2() + CO2(g) = CaCO3(s) + H2O(l) =>
Ca(OH)2() + CO2(g) = CaCO3(s) + H2O(l)
BaO2 + Cr2(SO4)3 + NaOH = BaSO4 + Na2CrO4 + H2O =>
3 BaO2 + Cr2(SO4)3 + 4 NaOH = 3 BaSO4 + 2 Na2CrO4 + 2 H2O
BaCl2 + AgNO3 = Cl2Ag + BaNO3 =>
BaCl2 + AgNO3 = Cl2Ag + BaNO3
Ca(C2H3O2)2*H2O + KCO3 = K(C2H3O2)2*H2O + CaCO3 =>
Ca(C2H3O2)2*H2O + KCO3 = K(C2H3O2)2*H2O + CaCO3
Al + HCl = AlCl3 + H2 =>
2 Al + 6 HCl = 2 AlCl3 + 3 H2
C4H9OH + CuO = C4H7OH + H2O + Cu =>
C4H9OH + CuO = C4H7OH + H2O + Cu
CaC2 + N = C + CaNCN =>
CaC2 + 2 N = C + CaNCN
Cl + KI = Cl(KI)2 =>
Cl + 2 KI = Cl(KI)2
Na2S + I2 + H2O = NaI + H2SO =>
Na2S + I2 + H2O = 2 NaI + H2SO
Ca(NO3)2 + Mg = Mg(NO3) + Ca =>
Ca(NO3)2 + 2 Mg = 2 Mg(NO3) + Ca
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/12/24
Equations balanced on 03/13/23
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