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化学反応式のバランス04/10/24

 前日に均衡した方程式 翌日に均衡がとれた方程式
あらゆる化学反応の方程式のバランスをとる
BaCl2 + Na2(SO4) = NaCl + Ba2(SO4)2 =>
2 BaCl2 + 2 Na2(SO4) = 4 NaCl + Ba2(SO4)2

FrO + O2 = Fr2O3 =>
4 FrO + O2 = 2 Fr2O3

K2Cr2O7 + H2SO4 + KI = I2 + Cr2(SO4)3 + K2SO4 + H2O =>
K2Cr2O7 + 7 H2SO4 + 6 KI = 3 I2 + Cr2(SO4)3 + 4 K2SO4 + 7 H2O

Ce(IO3)4 + H2O2C4 = Ce2(C2O4)3 + I2 + CO2 + H2O =>
14 Ce(IO3)4 + 24 H2O2C4 = 7 Ce2(C2O4)3 + 28 I2 + 54 CO2 + 24 H2O

Zn + HgSO4 = ZnSO4 + Hg2 =>
2 Zn + 2 HgSO4 = 2 ZnSO4 + Hg2

NaC6H5COO + HCl = NaCl + C6H5COOH =>
NaC6H5COO + HCl = NaCl + C6H5COOH

CaCO3 = CaO + CO2 =>
CaCO3 = CaO + CO2

Al(OH)3 + CuCl = AlCl3 + Cu3(OH)3 =>
Al(OH)3 + 3 CuCl = AlCl3 + Cu3(OH)3

CH4 + H2O = CO2 + H2 =>
CH4 + 2 H2O = CO2 + 4 H2

C5H10 + O2 = CO2 + H2O =>
2 C5H10 + 15 O2 = 10 CO2 + 10 H2O

CH3CH(OH)CH3 + H2O = CH3CH2CH2O + H3O =>
CH3CH(OH)CH3 + H2O = CH3CH2CH2O + H3O

KOH + CaCO3 = Ca(OH)2 + K2O + CO2 =>
2 KOH + CaCO3 = Ca(OH)2 + K2O + CO2

K(OH) + CuS = CuOH + KS =>
K(OH) + CuS = CuOH + KS

[Cu(H2O)4]{2+} + NH4OH = [Cu(H2O)4(NH3)2]{2+} + H2O =>
[Cu(H2O)4]{2+} + 2 NH4OH = [Cu(H2O)4(NH3)2]{2+} + 2 H2O

NaCl + AgNO3 + HNO3 = Na(NO3)2 + AgCl + H2 =>
2 NaCl + 2 AgNO3 + 2 HNO3 = 2 Na(NO3)2 + 2 AgCl + H2

SiO2 + CH3COOH = SiOOH + CH3COO =>
SiO2 + CH3COOH = SiOOH + CH3COO

CH4 + H2O = CO + H2 =>
CH4 + H2O = CO + 3 H2

H2PO4 + Mg(CO3)2 = Mg(PO4)2 + H2CO3 =>
2 H2PO4 + Mg(CO3)2 = Mg(PO4)2 + 2 H2CO3

Ba(s) + HNO3(aq) = H2(g) + Ba(NO3)2(aq) =>
Ba(s) + 2 HNO3(aq) = H2(g) + Ba(NO3)2(aq)

C13H8 + O2 = CO + H2O =>
2 C13H8 + 17 O2 = 26 CO + 8 H2O

CH3CH(OH)CH3 + H2O = CH3CH2CH2O + H3O =>
CH3CH(OH)CH3 + H2O = CH3CH2CH2O + H3O

Cl2 + NaOH = NaCl + NaClO3 + H2O =>
3 Cl2 + 6 NaOH = 5 NaCl + NaClO3 + 3 H2O

NiSO4*20H2O + Na2CO3 = NiCO3 + Na2SO4 + H2O =>
NiSO4*20H2O + Na2CO3 = NiCO3 + Na2SO4 + 20 H2O

Fe2O3 + Cu = Fe + CuO3 =>
Fe2O3 + Cu = 2 Fe + CuO3

CaClO + KCl = KClO3 + CaCl =>
3 CaClO + KCl = KClO3 + 3 CaCl

H2C2O4 + Ba(OH)2 = BaC2O4 + H2O =>
H2C2O4 + Ba(OH)2 = BaC2O4 + 2 H2O

Ba(No3)2 + KCl = BaCl2 + KNo3 =>
Ba(No3)2 + 2 KCl = BaCl2 + 2 KNo3

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

Sn{+4} + H2O = O2 + Sn{+2} + H{+} =>
2 Sn{+4} + 2 H2O = O2 + 2 Sn{+2} + 4 H{+}

C10H8 + H2SO4SO3 = C10H8O9S3 + H2SO4 =>
C10H8 + 3 H2SO4SO3 = C10H8O9S3 + 3 H2SO4

Mg2Si + H2O = SiH4 + Mg(OH)2 =>
Mg2Si + 4 H2O = SiH4 + 2 Mg(OH)2

CH3C00 + A1(OH)3(aq) = A1(C2H02)3(aq) + H2O(g) =>
3 CH3C00 + A1(OH)3(aq) = A1(C2H02)3(aq) + 3 H2O(g)

Ba(OH)2 + H2SO4 = BaSO4 + H2O =>
Ba(OH)2 + H2SO4 = BaSO4 + 2 H2O

Zn + NaNO3 + HCl = ZnCl2 + NH4Cl + NaCl + H2O =>
4 Zn + NaNO3 + 10 HCl = 4 ZnCl2 + NH4Cl + NaCl + 3 H2O

CH3CH2CH2CHO + Ag(NH3)2OH = CH3COONH4 + Ag + NH3 + H2O =>
CH3CH2CH2CHO + 6 Ag(NH3)2OH = 2 CH3COONH4 + 6 Ag + 10 NH3 + 3 H2O

C2H5NH2 + HNO3 = C2H5NO3 + NH3 = co2 + h2o + n2 =>
C2H5NH2 + HNO3 = C2H5NO3 + NH3

Fe2O3 + Cu = Fe2 + CuO3 =>
Fe2O3 + Cu = Fe2 + CuO3

Cu + HNO3 = Cu(NO3)2 + NO + H2O =>
3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

H2O + C2H4 = CH3CH2OH =>
H2O + C2H4 = CH3CH2OH

C2H5SH(g) + O2(g) = CO2(g) + H2O(g) + SO2(g) =>
2 C2H5SH(g) + 9 O2(g) = 4 CO2(g) + 6 H2O(g) + 2 SO2(g)

K2S2O3 + H3PO4 = K2PO4 + H3S2O3 =>
K2S2O3 + H3PO4 = K2PO4 + H3S2O3

CaCl2Sr(No3)2 = Ca(No3)2SrCl2 =>
CaCl2Sr(No3)2 = Ca(No3)2SrCl2

SnCl2 + NaOH = Sn(OH)2 + NaCl =>
SnCl2 + 2 NaOH = Sn(OH)2 + 2 NaCl

Cr2O3(s) + Al(s) = Al2O3(s) + Cr(s) =>
Cr2O3(s) + 2 Al(s) = Al2O3(s) + 2 Cr(s)

Ba(HS)2 + Cl2 + H2O = Ba(OH)2 + HCl + H2SO4 =>
Ba(HS)2 + 8 Cl2 + 10 H2O = Ba(OH)2 + 16 HCl + 2 H2SO4

Fe + Y2 = FeY3 =>
2 Fe + 3 Y2 = 2 FeY3

K2Cr2O7 + C2H5OH + H2SO4 = CH3COOH + Cr2(SO4)3 + H2O + K2SO4 =>
2 K2Cr2O7 + 3 C2H5OH + 8 H2SO4 = 3 CH3COOH + 2 Cr2(SO4)3 + 11 H2O + 2 K2SO4

[NH3CH2COOH]Br + NaOH = NH2CH2COONa + NaBr + H2O =>
[NH3CH2COOH]Br + 2 NaOH = NH2CH2COONa + NaBr + 2 H2O

CH3COONa + Ti(SO4)2 + H2O = TiO(OH)2 + CH3COOH + Na2SO4 =>
4 CH3COONa + Ti(SO4)2 + 3 H2O = TiO(OH)2 + 4 CH3COOH + 2 Na2SO4

Sr(OH)2*8H2O(s) + NH4Cl(s) = SrCl2(aq) + NH3(g) + H2O(l) =>
Sr(OH)2*8H2O(s) + 2 NH4Cl(s) = SrCl2(aq) + 2 NH3(g) + 10 H2O(l)

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あらゆる化学反応の方程式のバランスをとる
 前日に均衡した方程式 翌日に均衡がとれた方程式
方程式のバランス04/03/24
方程式のバランス03/11/24
方程式のバランス04/10/23
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