Equations balanced on the previous day | Equations balanced on the next day |
LiOH + Na(NO3) = NaOH + Li(NO3)
FeS2 + O2 + H2O = Fe2 + H2SO4 =>
2 FeS2 + 6 O2 + 4 H2O = Fe2 + 4 H2SO4
Fe3P2 = Fe + P =>
Fe3P2 = 3 Fe + 2 P
FeBr3 + Cl = Fe + BrCl =>
FeBr3 + 3 Cl = Fe + 3 BrCl
C3H8(g) + O2(g) = H2O(l) + C(aq) =>
C3H8(g) + 2 O2(g) = 4 H2O(l) + 3 C(aq)
HI(aq) + KHSO3(aq) = KI(aq) + H2SO3(aq) =>
HI(aq) + KHSO3(aq) = KI(aq) + H2SO3(aq)
CaOHNaSO4 = CaSO4NaOH =>
CaOHNaSO4 = CaSO4NaOH
HI(aq)CsOH(aq) = H2O(aq)CsI(aq) =>
HI(aq)CsOH(aq) = H2O(aq)CsI(aq)
NaCl + H2O2 = NaClO + H2O =>
NaCl + H2O2 = NaClO + H2O
CH3CH2COOH + H2O = CH3CH2COOH2 + OH =>
CH3CH2COOH + H2O = CH3CH2COOH2 + OH
NaCl + AlBr3 = Na(Br)3 + AlCl =>
NaCl + AlBr3 = Na(Br)3 + AlCl
I2 + O2 = I2O2 =>
I2 + O2 = I2O2
CaCO3 + Al2O3 = Al2(CO3)3 + CaO =>
3 CaCO3 + Al2O3 = Al2(CO3)3 + 3 CaO
NF3 + Al2O3 = AlF3 + N2 + O2 =>
4 NF3 + 2 Al2O3 = 4 AlF3 + 2 N2 + 3 O2
KI + HCN = KH + ICN =>
KI + HCN = KH + ICN
CaCl + Na2CrO4 = Ca2CrO4 + NaCl =>
2 CaCl + Na2CrO4 = Ca2CrO4 + 2 NaCl
Ba + O2 + H2 = Ba(OH)2 =>
Ba + O2 + H2 = Ba(OH)2
NaHCO3 + C6H8O7 = CO2 + H2O + NaC6 =>
18 NaHCO3 + 25 C6H8O7 = 60 CO2 + 109 H2O + 18 NaC6
CaCl2 + Al(NO3)3 = AlCl2 + Ca(NO3)3 =>
CaCl2 + Al(NO3)3 = AlCl2 + Ca(NO3)3
C6H10O5 + HNO3 = C12H14N6O22 + H2O =>
2 C6H10O5 + 6 HNO3 = C12H14N6O22 + 6 H2O
Cl7 + O2 = Cl2O7 =>
4 Cl7 + 49 O2 = 14 Cl2O7
Cr + H3O = CrH + H2O =>
Cr + H3O = CrH + H2O
Al3 + Fe3O = Al3O + Fe =>
Al3 + Fe3O = Al3O + 3 Fe
CaCl2 + Al(NO3)3 = AlCl2 + Ca(NO3)3 =>
CaCl2 + Al(NO3)3 = AlCl2 + Ca(NO3)3
CO4 + H2 = CH4 + H2O =>
CO4 + 6 H2 = CH4 + 4 H2O
Cr(NO3)3 + CuSO4 = Cr2(SO4)3 + Cu(NO3)2 =>
2 Cr(NO3)3 + 3 CuSO4 = Cr2(SO4)3 + 3 Cu(NO3)2
C14H10O2 + NaBH4 + CH3CH2OH = C14H14O2 + NaB(OCH2CH3) =>
5 C14H10O2 + 4 NaBH4 + 4 CH3CH2OH = 5 C14H14O2 + 4 NaB(OCH2CH3)
C14H10O2 + NaBH4 + CH3CH2OH = C14H14O2 + NaB(OCH2CH3) =>
5 C14H10O2 + 4 NaBH4 + 4 CH3CH2OH = 5 C14H14O2 + 4 NaB(OCH2CH3)
HCl + H2O = H3O + Cl =>
HCl + H2O = H3O + Cl
C4H9OH + CrO3 + H2SO4 = CH3COC2H5 + Cr2(SO4)3 + H2O =>
3 C4H9OH + 2 CrO3 + 3 H2SO4 = 3 CH3COC2H5 + Cr2(SO4)3 + 6 H2O
C14H10O2 + NaBH4 + CH3CH2OH = C14H14O2 + NaB(OCH2CH3) =>
5 C14H10O2 + 4 NaBH4 + 4 CH3CH2OH = 5 C14H14O2 + 4 NaB(OCH2CH3)
C2H3COOH + C2H5OH = C2H3COOC2H5 + H2O =>
C2H3COOH + C2H5OH = C2H3COOC2H5 + H2O
Na + Al2(CO3)3 = Al + Na2(CO3) =>
6 Na + Al2(CO3)3 = 2 Al + 3 Na2(CO3)
As2S5 + NH3 + H2O2 = (NH4)3AsO4 + (NH4)2SO4 + H2O =>
As2S5 + 16 NH3 + 20 H2O2 = 2(NH4)3AsO4 + 5(NH4)2SO4 + 12 H2O
C14H10O2 + NaBH4 + CH3CH2OH = C14H14O2 + NaB(OCH2CH3) =>
5 C14H10O2 + 4 NaBH4 + 4 CH3CH2OH = 5 C14H14O2 + 4 NaB(OCH2CH3)
C14H10O2 + NaBH4 + CH3CH2OH = C14H14O2 + NaB(OCH2CH3) =>
5 C14H10O2 + 4 NaBH4 + 4 CH3CH2OH = 5 C14H14O2 + 4 NaB(OCH2CH3)
FeSO4 + H2SO4 + KMnO4 = Fe(SO4)3 + H2O + K2SO4 + MnSO4 =>
5 FeSO4 + 16 H2SO4 + 4 KMnO4 = 5 Fe(SO4)3 + 16 H2O + 2 K2SO4 + 4 MnSO4
HC2H3O2(aq) + Na2CO3(aq) = H2O(l) + CO2(g) + NaC2H3O2(aq) =>
2 HC2H3O2(aq) + Na2CO3(aq) = H2O(l) + CO2(g) + 2 NaC2H3O2(aq)
Ba2Mn5O10 + C = BaO + Mn + CO =>
Ba2Mn5O10 + 8 C = 2 BaO + 5 Mn + 8 CO
NH + O2 = N2 + H2O =>
4 NH + O2 = 2 N2 + 2 H2O
Na2CO3 + HNO3 = NaNO3 + H2CO3 =>
Na2CO3 + 2 HNO3 = 2 NaNO3 + H2CO3
Na2O2 + H2SO4 + KI = I2 + Na2SO4 + K2SO4 + H2O =>
Na2O2 + 2 H2SO4 + 2 KI = I2 + Na2SO4 + K2SO4 + 2 H2O
Na2CO3 + HNO3 = NaNO3 + CO2 + H2O =>
Na2CO3 + 2 HNO3 = 2 NaNO3 + CO2 + H2O
Ba2S + K2CO3 = Ba2CO3 + K2S =>
Ba2S + K2CO3 = Ba2CO3 + K2S
NaCl + Ag + Pd = AgCl + NaPd =>
NaCl + Ag + Pd = AgCl + NaPd
Br + KI = BrI + K =>
Br + KI = BrI + K
Fe + N2 = Fe2N3 =>
4 Fe + 3 N2 = 2 Fe2N3
Sn + HNO3 = SnO2 + H2O + NO2 = =>
Sn + 4 HNO3 = SnO2 + 2 H2O + 4 NO2
HC2H3O2(aq) + Na2CO3(aq) = H2O(l) + CO2(g) + NaC2H3O2(aq) =>
2 HC2H3O2(aq) + Na2CO3(aq) = H2O(l) + CO2(g) + 2 NaC2H3O2(aq)
Cl + KOH = KCl + KClO3 + H2O =>
6 Cl + 6 KOH = 5 KCl + KClO3 + 3 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 05/03/24
Equations balanced on 06/02/23
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