| 前日に均衡した方程式 | 翌日に均衡がとれた方程式 |
2 NaOH + Cu(No3)2 = Cu(OH)2 + 2 Na(No3)
Pb + CH3COOH + KI = PbI2 + CH3COOK + H2 =>
Pb + 2 CH3COOH + 2 KI = PbI2 + 2 CH3COOK + H2
Me + S = Me2S =>
2 Me + S = Me2S
Ba(NO3)2 + K2SiO3 = KNO3 + BaSiO3 =>
Ba(NO3)2 + K2SiO3 = 2 KNO3 + BaSiO3
Ag(NO3)2 + K2S = AgS + KNO3 =>
Ag(NO3)2 + K2S = AgS + 2 KNO3
Na2O + NO5 = NaO + NO =>
4 Na2O + NO5 = 8 NaO + NO
C2H5OH + KMnO4 = H2O + CH3COOH + MnO2 + KOH =>
3 C2H5OH + 4 KMnO4 = H2O + 3 CH3COOH + 4 MnO2 + 4 KOH
Fe(OH)3 + HNO3 = Fe(NO3)3 + H2O =>
Fe(OH)3 + 3 HNO3 = Fe(NO3)3 + 3 H2O
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
Na2SO4 + BaCl2 = NaCl + BaSO4 =>
Na2SO4 + BaCl2 = 2 NaCl + BaSO4
HNO3 + Na2SO3 = H2O + SO2 + NaNO3 =>
2 HNO3 + Na2SO3 = H2O + SO2 + 2 NaNO3
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
K3P + Mn(NO3)2 = KNO3 + Mn3P2 =>
2 K3P + 3 Mn(NO3)2 = 6 KNO3 + Mn3P2
C2H4 + O3 = CH2O =>
3 C2H4 + 2 O3 = 6 CH2O
KMnO4 + MnSO4 + KOH = K2SO4 + K2MnO4 + H2O =>
4 KMnO4 + MnSO4 + 8 KOH = K2SO4 + 5 K2MnO4 + 4 H2O
ClOH = HClO =>
ClOH = HClO
C2H5OH + K2Cr2O7 + HCl = CH3COOH + CrCl3 + KCl + H2O =>
3 C2H5OH + 2 K2Cr2O7 + 16 HCl = 3 CH3COOH + 4 CrCl3 + 4 KCl + 11 H2O
Ba(NO3)2 + K2SiO3 = KNO3 + BaSiO3 =>
Ba(NO3)2 + K2SiO3 = 2 KNO3 + BaSiO3
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
C6H12O6 + H2O = C6H11O6 + H3O =>
C6H12O6 + H2O = C6H11O6 + H3O
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
C3H7OH + MnO4{-} = C3H6O + MnO2 + H2O + OH{-} =>
3 C3H7OH + 2 MnO4{-} = 3 C3H6O + 2 MnO2 + 2 H2O + 2 OH{-}
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
Na + CI2 = NaCI2 =>
Na + CI2 = NaCI2
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
FeBr3 + KOH = Br3OH + KFe =>
FeBr3 + KOH = Br3OH + KFe
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
Cu(OH)2 + H2SO4 = CuSO4 + H2O =>
Cu(OH)2 + H2SO4 = CuSO4 + 2 H2O
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
NaCO + BeI = NaIBeCO =>
NaCO + BeI = NaIBeCO
K2CO + HBr = K2Br + HCO =>
K2CO + HBr = K2Br + HCO
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
Na2CO3 + HCl = NaCl + H2O + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2
Cu(NO3)2 + Na2S = Na(NO3) + CuS =>
Cu(NO3)2 + Na2S = 2 Na(NO3) + CuS
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
K2CO + HBr = K2Br + HCO =>
K2CO + HBr = K2Br + HCO
Na2CO3 + HCl = NaCl + H2O + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2
K2Cr2O7 + HCl + C2H5OH = CrCl3 + CO2 + KCl + H2O =>
2 K2Cr2O7 + 16 HCl + C2H5OH = 4 CrCl3 + 2 CO2 + 4 KCl + 11 H2O
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
Ag2O3 + H2SO4 = Ag(SO4)3 + SO2 + H2O =>
Ag2O3 + 9 H2SO4 = 2 Ag(SO4)3 + 3 SO2 + 9 H2O
Al + HCl = AlCl3 + H2 =>
2 Al + 6 HCl = 2 AlCl3 + 3 H2
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
K2SO4 + MgSO4 + H2O = K2SO4*MgSO4*6H2O =>
K2SO4 + MgSO4 + 6 H2O = K2SO4*MgSO4*6H2O
K2Cr2O7 + C2H5OH + HCl = CrCl3 + CH3CHO + KCl + H2O =>
K2Cr2O7 + 3 C2H5OH + 8 HCl = 2 CrCl3 + 3 CH3CHO + 2 KCl + 7 H2O
AuCl3 + Ag = AgCl3 + Au =>
AuCl3 + Ag = AgCl3 + Au
CsF(s) + XeF6(s) = CsXeF7(s) =>
CsF(s) + XeF6(s) = CsXeF7(s)
Mg(OH)2 + Cu2CO3 = CuOH + MgCO3 =>
Mg(OH)2 + Cu2CO3 = 2 CuOH + MgCO3
Bi + HClO4 = Bi(ClO4)5 + H2 =>
2 Bi + 10 HClO4 = 2 Bi(ClO4)5 + 5 H2
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| 前日に均衡した方程式 | 翌日に均衡がとれた方程式 |
方程式のバランス09/10/24
方程式のバランス10/10/23
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