Printed from https://www.webqc.org

化学反応式のバランス12/03/24

 前日に均衡した方程式 翌日に均衡がとれた方程式
あらゆる化学反応の方程式のバランスをとる
Fe + Cr(NO3)3 = FeNO3 + Cr =>
3 Fe + Cr(NO3)3 = 3 FeNO3 + Cr

K(ClO3)3 = KCl3 + O2 =>
2 K(ClO3)3 = 2 KCl3 + 9 O2

H6TeO6 + AgCl = Ag6TeO6 + HCl =>
H6TeO6 + 6 AgCl = Ag6TeO6 + 6 HCl

Rb + S8 = Rb2S =>
16 Rb + S8 = 8 Rb2S

HNO3 + Mn(HCO3)2 = CO2 + H2O + Mn(NO3)2 =>
2 HNO3 + Mn(HCO3)2 = 2 CO2 + 2 H2O + Mn(NO3)2

C3H8(g) + O2(g) = CO2(aq) + H2O(g) =>
C3H8(g) + 5 O2(g) = 3 CO2(aq) + 4 H2O(g)

N2H4 + C3H7NO2 + NaOH = C3H8O + H2O + NaN3 =>
N2H4 + C3H7NO2 + NaOH = C3H8O + 2 H2O + NaN3

P4 + HNO3 = P2O5 + N2O + H2O =>
2 P4 + 10 HNO3 = 4 P2O5 + 5 N2O + 5 H2O

Ba(OH)2 + HI = Ba(I)2 + H2O =>
Ba(OH)2 + 2 HI = Ba(I)2 + 2 H2O

Cu + HNO3 = Cu(NO3)2 + NO + H2O =>
3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

C12H22O11 + K2Cr2O7 + H2SO4 = CO2 + Cr2(SO4)3 + K2SO4 + H2O =>
C12H22O11 + 8 K2Cr2O7 + 32 H2SO4 = 12 CO2 + 8 Cr2(SO4)3 + 8 K2SO4 + 43 H2O

C3H8O(l) + O2(g) = CO2(g) + H20(l) =>
10 C3H8O(l) + 25 O2(g) = 30 CO2(g) + 4 H20(l)

C12H22O11 + K2Cr2O7 + H2SO4 = CO2 + Cr2(SO4)3 + K2SO4 + H2O =>
C12H22O11 + 8 K2Cr2O7 + 32 H2SO4 = 12 CO2 + 8 Cr2(SO4)3 + 8 K2SO4 + 43 H2O

PbOH2SO4 = PbSO4H2O =>
PbOH2SO4 = PbSO4H2O

C12H22O11 + K2Cr2O7 + H2SO4 = CO2 + Cr2(SO4)3 + K2SO4 + H2O =>
C12H22O11 + 8 K2Cr2O7 + 32 H2SO4 = 12 CO2 + 8 Cr2(SO4)3 + 8 K2SO4 + 43 H2O

AgNO3 + NaOH = AgOH + NaNO3 =>
AgNO3 + NaOH = AgOH + NaNO3

K2SO4 + HCl = KCl + H2SO4 =>
K2SO4 + 2 HCl = 2 KCl + H2SO4

NH4OH + HCI = NH4CI + HOH =>
NH4OH + HCI = NH4CI + HOH

Be + N2 = Be3N2 =>
3 Be + N2 = Be3N2

CuCl*2H2O + Al = AlCl3 + Cu + H2O =>
3 CuCl*2H2O + Al = AlCl3 + 3 Cu + 6 H2O

FeCl3 + KSCN = Fe(SCN)3 + KCl =>
FeCl3 + 3 KSCN = Fe(SCN)3 + 3 KCl

Fe(NO3)3 + Na2(C2O4) = Fe2(C2O4)3 + Na(NO3) =>
2 Fe(NO3)3 + 3 Na2(C2O4) = Fe2(C2O4)3 + 6 Na(NO3)

AgNO3 + NaOH = AgOH + NaNO3 =>
AgNO3 + NaOH = AgOH + NaNO3

HCl = H2 + Cl2 =>
2 HCl = H2 + Cl2

Al(NH3) + NH3 = Al(NH3)6 =>
Al(NH3) + 5 NH3 = Al(NH3)6

Al + K2ZrF6 = ZrAl3 + K3AlF6 + KAlF4 =>
13 Al + 3 K2ZrF6 = 3 ZrAl3 + K3AlF6 + 3 KAlF4

HCl + KMnO4 + H2C2O4 = MnCl2 + CO2 + H2O + KCl =>
6 HCl + 2 KMnO4 + 5 H2C2O4 = 2 MnCl2 + 10 CO2 + 8 H2O + 2 KCl

KCl + C4H6O6 = KH6O6 + C4Cl =>
KCl + C4H6O6 = KH6O6 + C4Cl

HSiCl3 + H2O = H10Si10O15 + HCl =>
10 HSiCl3 + 15 H2O = H10Si10O15 + 30 HCl

Sr2(OH)2 + BaCl2 = BaOH + SrCl2 =>
Sr2(OH)2 + 2 BaCl2 = 2 BaOH + 2 SrCl2

Ag(s) + O2(s) = Ag2O(s) =>
4 Ag(s) + O2(s) = 2 Ag2O(s)

NH4Br + Cl2 = NH4Cl + Br2 =>
2 NH4Br + Cl2 = 2 NH4Cl + Br2

Mn3 + Ar = Mn2Ar =>
2 Mn3 + 3 Ar = 3 Mn2Ar

NaClO + MnSO4 + H2O = H2SO4 + MnO2 + NaCl =>
NaClO + MnSO4 + H2O = H2SO4 + MnO2 + NaCl

NH3 + Cl2 = N2 + Cl{-} + H{+} =>
2 NH3 + 3 Cl2 = N2 + 6 Cl{-} + 6 H{+}

C3H4 + Br2 = C3H4Br2 =>
C3H4 + Br2 = C3H4Br2

Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO

NaOH + CH4COOH = H2O + NaCH3COOH =>
NaOH + CH4COOH = H2O + NaCH3COOH

C2H5OH + CH3CHO = CH3CH(OC2H5)2 + H2O =>
2 C2H5OH + CH3CHO = CH3CH(OC2H5)2 + H2O

GeO2 + Na[BH4] + O = GeH4 + NaBO3 =>
GeO2 + Na[BH4] + O = GeH4 + NaBO3

Fe(SO4)3 + H2SO3 + H2O = FeSO4 + H2SO4 =>
Fe(SO4)3 + 2 H2SO3 + 2 H2O = FeSO4 + 4 H2SO4

NaHSO3(g) = Na2SO3(s) + SO2(g) + H2O(l) =>
2 NaHSO3(g) = Na2SO3(s) + SO2(g) + H2O(l)

J2O3 = J2 + O2 =>
2 J2O3 = 2 J2 + 3 O2

C6H5COOH + O2 = H2O + C02 =>
2 C6H5COOH + O2 = 6 H2O + 7 C02

H2O + HF = H3FO =>
H2O + HF = H3FO

ZnBr + Al3 = AlBr3 + Zn2 =>
18 ZnBr + 2 Al3 = 6 AlBr3 + 9 Zn2

HSO3 + NO3 = HSO4 + NO =>
2 HSO3 + NO3 = 2 HSO4 + NO

Cu(NO3)2*3H2O + C4H6O3 + Co(AcAc)3 = Cu(C2H3O2)2*3H2O + C2H3O2 + Co(AcAcNO2)3 =>
3 Cu(NO3)2*3H2O + 6 C4H6O3 + 2 Co(AcAc)3 = 3 Cu(C2H3O2)2*3H2O + 6 C2H3O2 + 2 Co(AcAcNO2)3

CH3CH2SH + O2 = CH3CH2SSCH2CH3 + H2O =>
4 CH3CH2SH + O2 = 2 CH3CH2SSCH2CH3 + 2 H2O

BaSe + Bi2Te3 = BaTe + Bi2Se3 =>
3 BaSe + Bi2Te3 = 3 BaTe + Bi2Se3

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63
あらゆる化学反応の方程式のバランスをとる
 前日に均衡した方程式 翌日に均衡がとれた方程式
方程式のバランス11/26/24
方程式のバランス11/03/24
方程式のバランス12/03/23
化学反応式の係数調整サイトへのご意見·ご感想
メニュー 実行 モル質量 気体の法則 ユニット 化学のツール 周期表 化学フォーラム(英語) 対称性 定数 貢献する お問い合わせ
引用する場合の表示はこちらから。