Printed from https://www.webqc.org

化学反応式のバランス12/15/24

 前日に均衡した方程式 翌日に均衡がとれた方程式
あらゆる化学反応の方程式のバランスをとる
AgNO3KBr = AgBr + KNO3 =>
AgNO3KBr = AgBr + KNO3

KMnO4 + AlCl3 + KHSO4 = Al2(SO4)3 + K2SO4 + MnSO4 + H2O + Cl2 =>
6 KMnO4 + 10 AlCl3 + 48 KHSO4 = 5 Al2(SO4)3 + 27 K2SO4 + 6 MnSO4 + 24 H2O + 15 Cl2

NaOH + H2SO4 = OH + NaH2SO4 =>
NaOH + H2SO4 = OH + NaH2SO4

Al + C6H8O7 = AlC6H5O7 + H2 =>
2 Al + 2 C6H8O7 = 2 AlC6H5O7 + 3 H2

KMnO4 + Na2C2O4 + HCl = MnCl + CO2 + H2O + NaCl2 + KCl =>
2 KMnO4 + 3 Na2C2O4 + 16 HCl = 2 MnCl + 6 CO2 + 8 H2O + 6 NaCl2 + 2 KCl

Ba + NaSO4 = Ba(SO4)2 + Na =>
Ba + 2 NaSO4 = Ba(SO4)2 + 2 Na

C6H5CHO + KOH + HCl = C6H5COOH + C6H5CH2OH + KCl =>
2 C6H5CHO + KOH + HCl = C6H5COOH + C6H5CH2OH + KCl

CH3Cl = CH3* + Cl* =>
CH3Cl = CH3* + Cl*

CuSO4*5H2O + NaOH = CuO + Na2SO4 + H2O =>
CuSO4*5H2O + 2 NaOH = CuO + Na2SO4 + 6 H2O

P + Br2 = PBr3 =>
2 P + 3 Br2 = 2 PBr3

Na2C3O4 + KMnO4 + H2SO4 = K2SO4 + Na2SO4 + H2O + MnSO4 + CO2 =>
5 Na2C3O4 + 6 KMnO4 + 14 H2SO4 = 3 K2SO4 + 5 Na2SO4 + 14 H2O + 6 MnSO4 + 15 CO2

Mg + O2 + H2O = Mg(OH)2 =>
2 Mg + O2 + 2 H2O = 2 Mg(OH)2

CH3COH + K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + CH3COOH + H2O =>
3 CH3COH + K2Cr2O7 + 4 H2SO4 = K2SO4 + Cr2(SO4)3 + 3 CH3COOH + 4 H2O

Fl + KI = I + FlK =>
Fl + KI = I + FlK

NH3(g) + ClF3(g) = HF(g) + N2(g) + Cl2 =>
2 NH3(g) + 2 ClF3(g) = 6 HF(g) + N2(g) + Cl2

N2H4 = N2 + H2 =>
N2H4 = N2 + 2 H2

FeSO4Zn(OH)2 = Fe(OH)2ZnSO4 =>
FeSO4Zn(OH)2 = Fe(OH)2ZnSO4

CoCl2 + NaHCO3 = Co(HCO3)2 + NaCl =>
CoCl2 + 2 NaHCO3 = Co(HCO3)2 + 2 NaCl

Ag(s) + HNO3(l) = NO(g) + H2O(l) + AgNO3(aq) =>
3 Ag(s) + 4 HNO3(l) = NO(g) + 2 H2O(l) + 3 AgNO3(aq)

AgCl = Ag + Cl2 =>
2 AgCl = 2 Ag + Cl2

Li2O(aq) + H2O(l) = LiOH =>
Li2O(aq) + H2O(l) = 2 LiOH

C6H5CHO + KOH + HCl = C6H5COOH + C6H5CH2OH + KCl =>
2 C6H5CHO + KOH + HCl = C6H5COOH + C6H5CH2OH + KCl

CO2 + H2O = C6H12O6 + O2 =>
6 CO2 + 6 H2O = C6H12O6 + 6 O2

COCl2 + NaHCO3 = CO2 + NaCl + H2O =>
COCl2 + 2 NaHCO3 = 3 CO2 + 2 NaCl + H2O

C3H8O + O2 = CO2 + H2O =>
2 C3H8O + 9 O2 = 6 CO2 + 8 H2O

Cr(s) + S8(s) = Cr2S3(S) =>
4 Cr(s) + S8(s) = 2 Cr2S3(S)

K2Cr2O7 + NaCl + H2SO4 = Cl2 + H2O + K2SO4 + Na2SO4 + Cr2(SO4)3 =>
K2Cr2O7 + 6 NaCl + 7 H2SO4 = 3 Cl2 + 7 H2O + K2SO4 + 3 Na2SO4 + Cr2(SO4)3

HOC6H5OH = H2OC6H5O =>
HOC6H5OH = H2OC6H5O

KHSO4 + K2S = H2S + K2SO4 =>
2 KHSO4 + K2S = H2S + 2 K2SO4

CoCl2 + NaHCO3 = CoCO3 + NaHCl2 =>
CoCl2 + NaHCO3 = CoCO3 + NaHCl2

Li2O(aq) + H2O(l) = LiOH(aq) =>
Li2O(aq) + H2O(l) = 2 LiOH(aq)

C6H5CHO + KOH + HCl = C6H5COOH + C6H5CH2OH + KCl =>
2 C6H5CHO + KOH + HCl = C6H5COOH + C6H5CH2OH + KCl

CrO5 + H2O2 + H{+} = Cr{3+} + H2O + O2 =>
2 CrO5 + 7 H2O2 + 6 H{+} = 2 Cr{3+} + 10 H2O + 7 O2

CH3CH2OH + K = CH3CH2OK + H2 =>
2 CH3CH2OH + 2 K = 2 CH3CH2OK + H2

NaBr + Ca(OH)2 = CaBr2 + NaOH =>
2 NaBr + Ca(OH)2 = CaBr2 + 2 NaOH

Fe(OH)3 = Fe2O3 + H2O =>
2 Fe(OH)3 = Fe2O3 + 3 H2O

K[Al(OH)4]CO2 = KHCO3Al(OH)3 =>
K[Al(OH)4]CO2 = KHCO3Al(OH)3

(CH3COO)3 + KHSO4 = KSO4 + CH3COOH =>
(CH3COO)3 + 3 KHSO4 = 3 KSO4 + 3 CH3COOH

KOH + SO2 = K2SO3 + H2O =>
2 KOH + SO2 = K2SO3 + H2O

Fe2(SO4)3 + Na(OH) = Fe(OH)3 + Na2SO4 =>
Fe2(SO4)3 + 6 Na(OH) = 2 Fe(OH)3 + 3 Na2SO4

Zn + Na2S2O3 = ZnS2O3 + Na =>
Zn + Na2S2O3 = ZnS2O3 + 2 Na

H2SO4 + NaOH = Na2SO4 + H2O =>
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O

MgCl + NaCo = MgCo + NaCl =>
MgCl + NaCo = MgCo + NaCl

Al(OH)3Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O =>
Al(OH)3Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O

AlPO4 + CH3COOH = H3PO4 + (CH3COO)3Al =>
AlPO4 + 3 CH3COOH = H3PO4 + (CH3COO)3Al

C8H10N4O2 + O2 + H2O = CO2 + NH3 =>
2 C8H10N4O2 + 13 O2 + 2 H2O = 16 CO2 + 8 NH3

CH3CH2OH + K = CH3CH2OK + H =>
CH3CH2OH + K = CH3CH2OK + H

BaO + Co2 = BaCo3 + O2 =>
2 BaO + 3 Co2 = 2 BaCo3 + O2

CO + H2 = CH3OH =>
CO + 2 H2 = CH3OH

Cr(s) + Pb{2+}(aq) = Cr{3+}(aq) + Pb(s) =>
2 Cr(s) + 3 Pb{2+}(aq) = 2 Cr{3+}(aq) + 3 Pb(s)

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45
あらゆる化学反応の方程式のバランスをとる
 前日に均衡した方程式 翌日に均衡がとれた方程式
方程式のバランス12/08/24
方程式のバランス11/15/24
方程式のバランス12/15/23
化学反応式の係数調整サイトへのご意見·ご感想
メニュー 実行 モル質量 気体の法則 ユニット 化学のツール 周期表 化学フォーラム(英語) 対称性 定数 貢献する お問い合わせ
引用する場合の表示はこちらから。