Printed from https://www.webqc.org

化学反応式のバランス01/11/25

 前日に均衡した方程式 翌日に均衡がとれた方程式
あらゆる化学反応の方程式のバランスをとる
Al + H2S = H2 + AlS =>
Al + H2S = H2 + AlS

FeCl3 + HClO4 = Fe(ClO4)3 + HCl =>
FeCl3 + 3 HClO4 = Fe(ClO4)3 + 3 HCl

CO2 + KOH = KHCO3 =>
CO2 + KOH = KHCO3

SO3{-2} + Cu(OH)2 = SO4{-2} + Cu(OH) + H2O =>
SO3{-2} + 2 Cu(OH)2 = SO4{-2} + 2 Cu(OH) + H2O

BaHPO4 + H2SO4 = BaSO4 + H3PO4 =>
BaHPO4 + H2SO4 = BaSO4 + H3PO4

Na + HOH = NaOH + H2 =>
2 Na + 2 HOH = 2 NaOH + H2

Na + H2O = NaOH + H =>
Na + H2O = NaOH + H

LiOH + CuCl = LiCl + CuOH =>
LiOH + CuCl = LiCl + CuOH

CO2 + F2 = CF4 + O2 =>
CO2 + 2 F2 = CF4 + O2

Pb(OH)4 + HPO3 = Pb(PO3)4 + H2O =>
Pb(OH)4 + 4 HPO3 = Pb(PO3)4 + 4 H2O

Ag(C2H3O2) = Ag + C2H3O2 =>
Ag(C2H3O2) = Ag + C2H3O2

J2 + KOH = KJO + H2O + KJ =>
J2 + 2 KOH = KJO + H2O + KJ

Hg{+2} + Cl{-} = HgCl4{-2} =>
Hg{+2} + 4 Cl{-} = HgCl4{-2}

Ni(CO3) + Al(OH)3 = Ni(OH)2 + Al2(CO3)3 =>
3 Ni(CO3) + 2 Al(OH)3 = 3 Ni(OH)2 + Al2(CO3)3

C8H10 + KMnO4 + H2SO4 = C6H5COOH + H2O + K2SO4 + MnSO4 =>
35 C8H10 + 54 KMnO4 + 81 H2SO4 = 40 C6H5COOH + 136 H2O + 27 K2SO4 + 54 MnSO4

KOH(aq) + CaCO3(s) = K2CO3 + Ca(OH)2 =>
2 KOH(aq) + CaCO3(s) = K2CO3 + Ca(OH)2

C3H8O3 + H3PO4 = C3H9O6P + H2O =>
C3H8O3 + H3PO4 = C3H9O6P + H2O

Zn + Pb(C2H3O2)2 = Pb + Zn(CH3COO)2 =>
Zn + Pb(C2H3O2)2 = Pb + Zn(CH3COO)2

Cu + Al(NO3)3 = AlCu + CuNO3 =>
4 Cu + Al(NO3)3 = AlCu + 3 CuNO3

C6H2O6 + O2 = CO2 + H2O1 =>
2 C6H2O6 + 7 O2 = 12 CO2 + 2 H2O1

Ba + H3AsO3 = Ba3(AsO3)2 + H2 =>
3 Ba + 2 H3AsO3 = Ba3(AsO3)2 + 3 H2

MgSO4Na2HPO4NH4OH = MgNH4PO4Na2SO4H2O =>
MgSO4Na2HPO4NH4OH = MgNH4PO4Na2SO4H2O

Na2HCO3 + HCl = CO2 + H2O + Na + Cl =>
Na2HCO3 + HCl = CO2 + H2O + 2 Na + Cl

Au + CaBr2 = Ca + AuBr2 =>
Au + CaBr2 = Ca + AuBr2

H2CO3 + Sn(OH)4 = H2O + Sn(CO3)2 =>
2 H2CO3 + Sn(OH)4 = 4 H2O + Sn(CO3)2

NaOH + Sn(OH)2 = H2O + Sn(NaO)2 =>
2 NaOH + Sn(OH)2 = 2 H2O + Sn(NaO)2

KMnO4 + C2H4 + H2SO4 = CH2O2 + H2O + K2SO4 + MnSO4 =>
8 KMnO4 + 5 C2H4 + 12 H2SO4 = 10 CH2O2 + 12 H2O + 4 K2SO4 + 8 MnSO4

H2C4O4H4 + KOH = K2C4O4H4 + H2O =>
H2C4O4H4 + 2 KOH = K2C4O4H4 + 2 H2O

H2 + K = H2K =>
H2 + K = H2K

CH3ONa + C2H4O2 = C2H3NaO2 + CH4O =>
CH3ONa + C2H4O2 = C2H3NaO2 + CH4O

Zn + K2CrO7 + H2SO4 = ZnSO4 + K2SO4 + H2O + Cr2(SO4)2 =>
10 Zn + 2 K2CrO7 + 14 H2SO4 = 10 ZnSO4 + 2 K2SO4 + 14 H2O + Cr2(SO4)2

AgNO3 + Li2S = Ag2S + LiNO3 =>
2 AgNO3 + Li2S = Ag2S + 2 LiNO3

LiOH + Na2O = Li2O + NaOH =>
2 LiOH + Na2O = Li2O + 2 NaOH

HN3 + HONH2 = H2N2N2 + H2O =>
HN3 + HONH2 = H2N2N2 + H2O

NH3HCl = NH4Cl =>
NH3HCl = NH4Cl

Li3PO4 + SnCl2 = LiCl + Sn3(PO4)2 =>
2 Li3PO4 + 3 SnCl2 = 6 LiCl + Sn3(PO4)2

KMnO4 + H2SO4 + Na2C2O4 = CO2 + K2SO4 + Na2SO4 + H2O + MnSO4 =>
2 KMnO4 + 8 H2SO4 + 5 Na2C2O4 = 10 CO2 + K2SO4 + 5 Na2SO4 + 8 H2O + 2 MnSO4

CH4O + C6H5OCOOH = C6H5OCOOC2H4 + H2O =>
21 CH4O + 15 C6H5OCOOH = 14 C6H5OCOOC2H4 + 24 H2O

CO + H2O + SO3 = C6H6OS + O2 =>
12 CO + 6 H2O + 2 SO3 = 2 C6H6OS + 11 O2

CH3CH2COOH + NaCN = CH3CH2COCN + NaOH =>
CH3CH2COOH + NaCN = CH3CH2COCN + NaOH

Na2SO4 + CoCl2 = Na2Co + Cl2SO4 =>
Na2SO4 + CoCl2 = Na2Co + Cl2SO4

FeCI3 + Na2CO3 = FeCO3 + Na2CI3 =>
FeCI3 + Na2CO3 = FeCO3 + Na2CI3

Fe(PO4) + Li(NO3) = Fe(NO3)3 + Li3(PO4) =>
Fe(PO4) + 3 Li(NO3) = Fe(NO3)3 + Li3(PO4)

Mn + NO3 = MnO2 + NO =>
Mn + NO3 = MnO2 + NO

HSCH2COO + NH4 = HSCH2COOH + NH3 =>
HSCH2COO + NH4 = HSCH2COOH + NH3

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

Fe + CaCO3 + H2O = Fe2(CO3)3 + Ca(OH)2 + H2 =>
2 Fe + 3 CaCO3 + 6 H2O = Fe2(CO3)3 + 3 Ca(OH)2 + 3 H2

C7H6O2 + K2CO3 = C7H5O2K2 + HCO3 =>
C7H6O2 + K2CO3 = C7H5O2K2 + HCO3

FeCl3(aq) + NaOH = Fe(OH)3 + NaCl =>
FeCl3(aq) + 3 NaOH = Fe(OH)3 + 3 NaCl

FeS2 + H2O + NO3{-} = Fe(OH)3 + N2 + H{+} + SO4{2-} =>
2 FeS2 + 4 H2O + 6 NO3{-} = 2 Fe(OH)3 + 3 N2 + 2 H{+} + 4 SO4{2-}

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
あらゆる化学反応の方程式のバランスをとる
 前日に均衡した方程式 翌日に均衡がとれた方程式
方程式のバランス01/04/25
方程式のバランス12/12/24
方程式のバランス01/11/24
化学反応式の係数調整サイトへのご意見·ご感想
メニュー 実行 モル質量 気体の法則 ユニット 化学のツール 周期表 化学フォーラム(英語) 対称性 定数 貢献する お問い合わせ
引用する場合の表示はこちらから。