| 前日に均衡した方程式 |
2 CH2O + 6 CuSO4 + 12 NaOH = 2 CHOO + 3 Cu2O + 6 Na2SO4 + 7 H2O
XeF2 + OH{-} = Xe + O2 + F{-} + H2O =>
2 XeF2 + 4 OH{-} = 2 Xe + O2 + 4 F{-} + 2 H2O
CH3COOH + NaHCO3 = H2 + CH3COONa + HCO3 =>
2 CH3COOH + 2 NaHCO3 = H2 + 2 CH3COONa + 2 HCO3
K2Cr2O7 + H2O + O2 = KOH + Cr2O7 =>
2 K2Cr2O7 + 2 H2O + O2 = 4 KOH + 2 Cr2O7
Zn(OH)Cl + NaOH = Zn(OH)2 + NaCl =>
Zn(OH)Cl + NaOH = Zn(OH)2 + NaCl
Cr(OH)3 + NaClO + NaOH = Na2CrO4 + NaCl + H2O =>
2 Cr(OH)3 + 3 NaClO + 4 NaOH = 2 Na2CrO4 + 3 NaCl + 5 H2O
HBr + Cl2 = HCl + Br2 =>
2 HBr + Cl2 = 2 HCl + Br2
NaH + B2H6 = NaBH4 =>
2 NaH + B2H6 = 2 NaBH4
(Cu2(OH)2CO3) = CuO + H2O + CO2 =>
(Cu2(OH)2CO3) = 2 CuO + H2O + CO2
CH2BrCOOH + KOH = KC2H2BrO2 + H2O =>
CH2BrCOOH + KOH = KC2H2BrO2 + H2O
SO3(g) + H2O(l) = H2SO4(aq) =>
SO3(g) + H2O(l) = H2SO4(aq)
C2H5OH + OH{-} = CO2 + H2O + e =>
C2H5OH + 12 OH{-} = 2 CO2 + 9 H2O + 12e
Iron(ii)chloride + sodium = sodiumchloride + iron =>
FeCl2 + 2 Na = 2 NaCl + Fe
Mg1(OH)2 = Mg2O2 + H2O =>
2 Mg1(OH)2 = Mg2O2 + 2 H2O
AgNO3 + NH2CH2COOH = Ag2O + CO2 + N2 + H2O =>
18 AgNO3 + 10 NH2CH2COOH = 9 Ag2O + 20 CO2 + 14 N2 + 25 H2O
C10H16 + Cl2 = C + HClH20 =>
21 C10H16 + 8 Cl2 = 210 C + 16 HClH20
CuSO4 + Ba(NO3)2 = Cu(NO3)3 + Ba3(SO4)2 =>
2 CuSO4 + 3 Ba(NO3)2 = 2 Cu(NO3)3 + Ba3(SO4)2
Sc + OH = Sc(OH)3 =>
Sc + 3 OH = Sc(OH)3
KMnO4 + NH3 + KOH = K2MnO4 + NO2 + H2O =>
7 KMnO4 + NH3 + 7 KOH = 7 K2MnO4 + NO2 + 5 H2O
MgO + HCl = MgCl2 + H2O =>
MgO + 2 HCl = MgCl2 + H2O
V2S5 + O2 = VOSO4 + SO3 =>
2 V2S5 + 19 O2 = 4 VOSO4 + 6 SO3
H2O + Na2HCO3 = H2CO3 + Na + OH =>
H2O + Na2HCO3 = H2CO3 + 2 Na + OH
CH2BrCOOH + KOH = KC2H2BrO2 + H2O =>
CH2BrCOOH + KOH = KC2H2BrO2 + H2O
Na + FeO2 = Na2O + Fe =>
4 Na + FeO2 = 2 Na2O + Fe
Fe + C2H3O2 = Fe(C2H3O2)3 =>
Fe + 3 C2H3O2 = Fe(C2H3O2)3
HNO3 + BaOH = Ba + H2O + NO3 =>
HNO3 + BaOH = Ba + H2O + NO3
NH4OH + Cl3Fe = Fe + NH4Cl + OH =>
3 NH4OH + Cl3Fe = Fe + 3 NH4Cl + 3 OH
H3N + NaCl = Na3N + HCl =>
H3N + 3 NaCl = Na3N + 3 HCl
CH2BrCOOH + KOH = KC2H2BrO2 + H2O =>
CH2BrCOOH + KOH = KC2H2BrO2 + H2O
Bi + Fe = BiFe =>
Bi + Fe = BiFe
HF(aq) = H(aq) + F(aq) =>
HF(aq) = H(aq) + F(aq)
NaBr + K2Cr2O7 + H2SO4 = Br2 + Na2SO4 + Cr2(SO4)3 + K2SO4 + H2O =>
6 NaBr + K2Cr2O7 + 7 H2SO4 = 3 Br2 + 3 Na2SO4 + Cr2(SO4)3 + K2SO4 + 7 H2O
Cl2 + BrK = KCl + Br2 =>
Cl2 + 2 BrK = 2 KCl + Br2
CrO3 + Na2S2O5 + H2SO4 = Cr2(SO4)3 + NaSO4 + H2O =>
2 CrO3 + Na2S2O5 + 3 H2SO4 = Cr2(SO4)3 + 2 NaSO4 + 3 H2O
H + HgSO4 = H2SO4 + Hg =>
2 H + HgSO4 = H2SO4 + Hg
NH4 + PbO = Pb + H2O + N2 =>
2 NH4 + 4 PbO = 4 Pb + 4 H2O + N2
C6H126(s) + O2(g) = CO2(g) + H2O(g) =>
2 C6H126(s) + 75 O2(g) = 12 CO2(g) + 126 H2O(g)
H2O + Ca(C2H3O2)2 = CaO + HC2H3O2 =>
H2O + Ca(C2H3O2)2 = CaO + 2 HC2H3O2
C2H5NH2 + NaNO2 + HCl = C2H5OH + N2 + NaCl + H2O =>
C2H5NH2 + NaNO2 + HCl = C2H5OH + N2 + NaCl + H2O
CH2BrCOOH + KOH = KC2H2BrO2 + H2O =>
CH2BrCOOH + KOH = KC2H2BrO2 + H2O
K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO
SO2 + H2O = H2SO4 + H =>
SO2 + 2 H2O = H2SO4 + 2 H
CH2BrCOOH + KOH = KC2H2BrO2 + H2O =>
CH2BrCOOH + KOH = KC2H2BrO2 + H2O
Na2CO3 + CuSO4 = Na2SO4 + CuCO3 =>
Na2CO3 + CuSO4 = Na2SO4 + CuCO3
K[Sn(OH)3] + Br2 + KOH = KBr + K[Sn(OH)5] =>
K[Sn(OH)3] + Br2 + 2 KOH = 2 KBr + K[Sn(OH)5]
CH2BrCOOH + KOH = KC2H2BrO2 + H2O =>
CH2BrCOOH + KOH = KC2H2BrO2 + H2O
OH{-} + Cr(OH)3 + Cl2 = H2O + CrO4{2-} + Cl{-} =>
10 OH{-} + 2 Cr(OH)3 + 3 Cl2 = 8 H2O + 2 CrO4{2-} + 6 Cl{-}
[Co(NH3)5Cl]Cl2 + NH3 = NH3Cl + [Co(NH3)5Cl] =>
[Co(NH3)5Cl]Cl2 + 2 NH3 = 2 NH3Cl + [Co(NH3)5Cl]
Na + S + O + H2O = Na2SO4(H2O)10 =>
2 Na + S + 4 O + 10 H2O = Na2SO4(H2O)10
CH3COCH2CaCl2 + H = H(CH3COCH2CaCl2) =>
CH3COCH2CaCl2 + H = H(CH3COCH2CaCl2)
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| 前日に均衡した方程式 |
方程式のバランス12/19/24
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