前日に均衡した方程式 |
BaCl2 + H2SO4 = BaSO4 + 2 HCl(classification)
SnCl2(aq) + HgCl2(aq) = SnCl4(aq) + Hg2Cl2(s) =>
SnCl2(aq) + 2 HgCl2(aq) = SnCl4(aq) + Hg2Cl2(s)
S + NHO3 = H2SO4 + NO =>
S + 2 NHO3 = H2SO4 + 2 NO
FeS2 + Cl2 = Fe2Cl3 + S2Cl2 =>
4 FeS2 + 7 Cl2 = 2 Fe2Cl3 + 4 S2Cl2
Li + S8 = Li2S =>
16 Li + S8 = 8 Li2S
CH3CH2CHOHCH3 + Na2Cr2O7 + H2SO4 = CH3CH2COCH3 + Cr2(SO4)3 + Na2SO4 + H2O =>
3 CH3CH2CHOHCH3 + Na2Cr2O7 + 4 H2SO4 = 3 CH3CH2COCH3 + Cr2(SO4)3 + Na2SO4 + 7 H2O
Hg2NH3 + Cl2 + HNO3 = Hg2Cl + NH3NO3 + HCl =>
Hg2NH3 + Cl2 + HNO3 = Hg2Cl + NH3NO3 + HCl
FeS + O2 = SO3 + FeO =>
FeS + 2 O2 = SO3 + FeO
Cu + H2O = CuO + H2 =>
Cu + H2O = CuO + H2
I2 + H3 = HI =>
3 I2 + 2 H3 = 6 HI
C4H10O + KMnO4 = C4H8O2 + K + MnO2 + H2O =>
C4H10O + KMnO4 = C4H8O2 + K + MnO2 + H2O
CoSO4 + K2Cr2O7 + H2SO4 = Co(SO4)3 + K2SO4 + Cr2(SO4)3 + H2O =>
3 CoSO4 + 2 K2Cr2O7 + 14 H2SO4 = 3 Co(SO4)3 + 2 K2SO4 + 2 Cr2(SO4)3 + 14 H2O
C13H22O2 + O2 = CO2 + H2O =>
2 C13H22O2 + 35 O2 = 26 CO2 + 22 H2O
CaO + Na = Na2O + Ca =>
CaO + 2 Na = Na2O + Ca
C2H4O2 + H2O = CH3OOH =>
C2H4O2 + 2 H2O = 2 CH3OOH
Ce(OH)2 + KMnO4 + H2O = MnO2 + Ce(OH)4 + KOH =>
3 Ce(OH)2 + 2 KMnO4 + 4 H2O = 2 MnO2 + 3 Ce(OH)4 + 2 KOH
C5H18 + O2 = CO2(g) + H2O(g) =>
2 C5H18 + 19 O2 = 10 CO2(g) + 18 H2O(g)
Ba(OH)2(aq) + SO3(d) = BaSO4(k) + H2O(s) =>
Ba(OH)2(aq) + SO3(d) = BaSO4(k) + H2O(s)
KHC8H4O4 + Ca(OH)2 = CaKC8H3O4 + H2O =>
KHC8H4O4 + Ca(OH)2 = CaKC8H3O4 + 2 H2O
C2H6CHNH2CHCOOH + O2 = CO2 + H2O + NH3 =>
C2H6CHNH2CHCOOH + 6 O2 = 5 CO2 + 4 H2O + NH3
SrCO3 + Al(NO3)3*9H2O + (NH2)2CO = Sr4Al14O25 + H2O + CO2 + N2 =>
4 SrCO3 + 14 Al(NO3)3*9H2O + 35(NH2)2CO = Sr4Al14O25 + 196 H2O + 39 CO2 + 56 N2
NO + O3 + OH = HNO3 =>
3 NO + O3 + 3 OH = 3 HNO3
FrClO = Fr + ClO =>
FrClO = Fr + ClO
La(OH)2Cl = H2O + LaClO =>
La(OH)2Cl = H2O + LaClO
Ca2O2 + HCl = CaCl2 + H2O =>
Ca2O2 + 4 HCl = 2 CaCl2 + 2 H2O
BaCl2 + Na(C2H3O2) = Ba(C2H3O2) + NaCl2 =>
BaCl2 + Na(C2H3O2) = Ba(C2H3O2) + NaCl2
C6H8 + O2 = CO2 + H2O =>
C6H8 + 8 O2 = 6 CO2 + 4 H2O
Sn + Cu(SO3) = Sn(SO3) + Cu =>
Sn + Cu(SO3) = Sn(SO3) + Cu
NH3 + HClO4 = NH4{+} + ClO4{-} =>
NH3 + HClO4 = NH4{+} + ClO4{-}
Ce(CH3COO)3 + H2O2 + H2O = Ce(OH)3(OOH) + CH3COOH =>
2 Ce(CH3COO)3 + 3 H2O2 + 4 H2O = 2 Ce(OH)3(OOH) + 6 CH3COOH
TlClO4 + TcAsO4 = Tl4(AsO4)3 + Tc3(ClO4)4 =>
4 TlClO4 + 3 TcAsO4 = Tl4(AsO4)3 + Tc3(ClO4)4
SO4 + NaOH = Na2SO4 + OH =>
SO4 + 2 NaOH = Na2SO4 + 2 OH
MnCO3 + HI = MnI + HCO3 =>
MnCO3 + HI = MnI + HCO3
Fe + H2 = Fe3H2 =>
3 Fe + H2 = Fe3H2
SiI4 = Si + I =>
SiI4 = Si + 4 I
CH3CH2CHBr + KOH(alcoholic) = CH3CH2CHOH + KBr =>
CH3CH2CHBr + KOH(alcoholic) = CH3CH2CHOH + KBr
KCr2O7 + HI + HClO4 = KClO4 + Cr(ClO4)2 + H2O + I2 =>
2 KCr2O7 + 18 HI + 10 HClO4 = 2 KClO4 + 4 Cr(ClO4)2 + 14 H2O + 9 I2
HOCl = H{+} + OCl{-} =>
HOCl = H{+} + OCl{-}
*CaCl2(aq) + Na2CO3(aq) = CaCO3(s) + NaCl(aq) =>
*CaCl2(aq) + Na2CO3(aq) = CaCO3(s) + 2 NaCl(aq)
FeCl3 + F = Fe + ClF =>
FeCl3 + 3 F = Fe + 3 ClF
K + HNO3 = KNO3 + N2 + H2O =>
10 K + 12 HNO3 = 10 KNO3 + N2 + 6 H2O
K2CIO15 + MnO10 = MnCIO15 + K2O5 + O9 =>
9 K2CIO15 + 9 MnO10 = 9 MnCIO15 + 9 K2O5 + 5 O9
H2SO3 + Na2SO4 = Na2SO3 + H2SO4 =>
H2SO3 + Na2SO4 = Na2SO3 + H2SO4
Fe(NH4)2(SO4)2*6H2O + FeCO3 = Fe2O3 + C + (NH4) + (SO4) + H2O =>
Fe(NH4)2(SO4)2*6H2O + FeCO3 = Fe2O3 + C + 2(NH4) + 2(SO4) + 6 H2O
NH3 + HOH + Cr(NO3)3 = Cr(OH)3 + NH4NO3 =>
3 NH3 + 3 HOH + Cr(NO3)3 = Cr(OH)3 + 3 NH4NO3
CH3CO2H(aq) + KOH(aq) = KCH3CO2(aq) + H2O(l) =>
CH3CO2H(aq) + KOH(aq) = KCH3CO2(aq) + H2O(l)
CuH10 + O2 = CuO + H10O2 =>
2 CuH10 + 3 O2 = 2 CuO + 2 H10O2
Ti(MnO4)4 + Fe2O3 = TiO2 + Fe(MnO4)3 =>
3 Ti(MnO4)4 + 2 Fe2O3 = 3 TiO2 + 4 Fe(MnO4)3
Na2CO3 + HCl = NaCl + H2O + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2
FeS + HNO3 = Fe(NO3)3 + S + H2O + NO =>
FeS + 4 HNO3 = Fe(NO3)3 + S + 2 H2O + NO
あらゆる化学反応の方程式のバランスをとる
前日に均衡した方程式 |
方程式のバランス01/25/25
方程式のバランス02/24/24
化学反応式の係数調整サイトへのご意見·ご感想