| 前日に均衡した方程式 | 翌日に均衡がとれた方程式 |
2 NaOH + 2 Ca = 2 CaO + 2 Na + H2
(NH4)10W12O41*5H2O + HNO3 + H2O = WO3*H2O + NH4NO3 =>
(NH4)10W12O41*5H2O + 10 HNO3 + 2 H2O = 12 WO3*H2O + 10 NH4NO3
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
H2SO4 + K4Fe(CN)6 + KMnO4 = CO2 + Fe2(SO4)3 + H2O + HNO3 + KHSO4 + MnSO4 =>
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122 MnSO4
PhCH3 + KMnO4 + H2SO4 = PhCOOH + K2SO4 + MnSO4 + H2O =>
5 PhCH3 + 6 KMnO4 + 9 H2SO4 = 5 PhCOOH + 3 K2SO4 + 6 MnSO4 + 14 H2O
C6H5COOH + O2 = CO2 + H2O =>
2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O
K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO
H2SO3 + NaOH = Na2SO3 + H2O =>
H2SO3 + 2 NaOH = Na2SO3 + 2 H2O
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
H2SO3 + NaOH = Na2SO3 + H2O =>
H2SO3 + 2 NaOH = Na2SO3 + 2 H2O
Li + Br2 = LiBr =>
2 Li + Br2 = 2 LiBr
K2Cr2O7 + CH3CH3CH3COH + H2SO4 = Cr2(SO4)3 + CH3COOH + K2SO4 + H2O =>
4 K2Cr2O7 + 3 CH3CH3CH3COH + 16 H2SO4 = 4 Cr2(SO4)3 + 6 CH3COOH + 4 K2SO4 + 19 H2O
(CaSO4*2H2O) = CaSO4*H2O + H2O =>
(CaSO4*2H2O) = CaSO4*H2O + H2O
KOH + Mg + Li = LiOH + KMg2 =>
KOH + 2 Mg + Li = LiOH + KMg2
C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
Fe(NO3)3 + Sr(ClO3)2 = Fe(ClO3)3 + Sr(NO3)2 =>
2 Fe(NO3)3 + 3 Sr(ClO3)2 = 2 Fe(ClO3)3 + 3 Sr(NO3)2
H6Si2 + O2 = SiO2 + H2O =>
2 H6Si2 + 7 O2 = 4 SiO2 + 6 H2O
Cu(SO4)2 + HOH = H2(SO4) + Cu(OH)4 =>
Cu(SO4)2 + 4 HOH = 2 H2(SO4) + Cu(OH)4
Sr + Mn2O4 = Mn + SrO =>
4 Sr + Mn2O4 = 2 Mn + 4 SrO
CH3CH2COH + Ag(NH3)2OH = CH3CH2COONH4 + Ag + NH3 + H2O =>
CH3CH2COH + 2 Ag(NH3)2OH = CH3CH2COONH4 + 2 Ag + 3 NH3 + H2O
(NH4)3PO4 + CuSO4 = NH4SO4 + Cu3PO4 =>
(NH4)3PO4 + 3 CuSO4 = 3 NH4SO4 + Cu3PO4
AlCl3(aq) + Al2(SO4)3(aq) = Al(SO4)3(aq) + Al2Cl3(s) =>
AlCl3(aq) + Al2(SO4)3(aq) = Al(SO4)3(aq) + Al2Cl3(s)
Ca(OCl)2 + H2O2 = HOCl + Ca(OH)2 + O2 =>
Ca(OCl)2 + 2 H2O2 = 2 HOCl + Ca(OH)2 + O2
CaS(aq) + NaCl(aq) = CaCl + NaS =>
CaS(aq) + NaCl(aq) = CaCl + NaS
Pb + HPO4 = PbHPO4 =>
Pb + HPO4 = PbHPO4
CH4 + HNO3 = C2H6 + NO2 + H2O =>
2 CH4 + 2 HNO3 = C2H6 + 2 NO2 + 2 H2O
C2H5OH + CH3COOH = C3H6O2 + H2O =>
C2H5OH + 2 CH3COOH = 2 C3H6O2 + H2O
C5H6S2 + O2 = CO2 + H2O + SO2 =>
2 C5H6S2 + 17 O2 = 10 CO2 + 6 H2O + 4 SO2
C7H6O3 + NaOH = H2O + C7H5O3 + Na =>
C7H6O3 + NaOH = H2O + C7H5O3 + Na
HNO2 + Ti(OH)4 = H2O + Ti(NO2)4 =>
4 HNO2 + Ti(OH)4 = 4 H2O + Ti(NO2)4
C2H4O2 + K2CO3 + H2O = K2C2H6O4 + CO2 =>
C2H4O2 + K2CO3 + H2O = K2C2H6O4 + CO2
Cu(SO4) + Sn = Sn(SO4) + Cu =>
Cu(SO4) + Sn = Sn(SO4) + Cu
K2Cr2O7 + H2SO4 + C4H9OH = Cr2(SO4)3 + K2SO4 + H2O + C4H8O2 =>
2 K2Cr2O7 + 8 H2SO4 + 3 C4H9OH = 2 Cr2(SO4)3 + 2 K2SO4 + 11 H2O + 3 C4H8O2
Al(OH)3(s) + NH3(aq) = NAl + H2O =>
Al(OH)3(s) + NH3(aq) = NAl + 3 H2O
NaClO + C12H22O = H2O + CO2 + NaCl =>
34 NaClO + C12H22O = 11 H2O + 12 CO2 + 34 NaCl
Au + Co{+3} = Au{+3} + Co{+2} =>
Au + 3 Co{+3} = Au{+3} + 3 Co{+2}
C6H5CH3 + CO2 = C6H5COOH + H2O =>
5 C6H5CH3 + 7 CO2 = 6 C6H5COOH + 2 H2O
Al + HCl = AlCl3 + H2 =>
2 Al + 6 HCl = 2 AlCl3 + 3 H2
C5H8 + K2Cr2O7 + H2SO4 = C6H5COOH + K2SO4 + Cr2(SO4)3 + H2O =>
21 C5H8 + 23 K2Cr2O7 + 92 H2SO4 = 15 C6H5COOH + 23 K2SO4 + 23 Cr2(SO4)3 + 131 H2O
Cu3(SO4)2 + H5 = H3SO4 + Cu =>
5 Cu3(SO4)2 + 6 H5 = 10 H3SO4 + 15 Cu
AlCl3 + Ca(OH)2 = Al(OH)3 + CaCl2 =>
2 AlCl3 + 3 Ca(OH)2 = 2 Al(OH)3 + 3 CaCl2
Co(C2H3O2)2*4H2O(l) = Co(C2H3O2)2 + H2O =>
Co(C2H3O2)2*4H2O(l) = Co(C2H3O2)2 + 4 H2O
PbSO4 + Zn = Pb + ZnSO4 =>
PbSO4 + Zn = Pb + ZnSO4
Fe(OH)3 + H2SO4 = Fe2(SO4)3 + H2O =>
2 Fe(OH)3 + 3 H2SO4 = Fe2(SO4)3 + 6 H2O
K4Fe(CN)6 + KMnO4 + HCl = KCl + FeCl3 + MnCl2 + CO2 + HNO2 + H2O =>
5 K4Fe(CN)6 + 49 KMnO4 + 182 HCl = 69 KCl + 5 FeCl3 + 49 MnCl2 + 30 CO2 + 30 HNO2 + 76 H2O
AlCl3(aq) + AgNO3(aq) = AgCl(aq) + Al(NO3)3(s) =>
AlCl3(aq) + 3 AgNO3(aq) = 3 AgCl(aq) + Al(NO3)3(s)
C18H32O2 + C + O2 = C4O2H6 =>
3 C18H32O2 + 10 C + 13 O2 = 16 C4O2H6
NH3 + AlCl3 = AlN + HCl =>
NH3 + AlCl3 = AlN + 3 HCl
Bi + Sb + Dy + Te = Bi100Sb95Dy5Te30 =>
100 Bi + 95 Sb + 5 Dy + 30 Te = Bi100Sb95Dy5Te30
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| 前日に均衡した方程式 | 翌日に均衡がとれた方程式 |
方程式のバランス01/28/25
方程式のバランス02/27/24
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