Equations balanced on the previous day | Equations balanced on the next day |
LiBr + NaOH = LiOH + NaBr
KMnO4 + H2SO4 + Br2 = MnSO4 + KBrO3 + H2O =>
2 KMnO4 + 2 H2SO4 + Br2 = 2 MnSO4 + 2 KBrO3 + 2 H2O
H2SO4 + KMnO4 + KCl = Cl2 + MnSO4 + K2SO4 + H2O =>
8 H2SO4 + 2 KMnO4 + 10 KCl = 5 Cl2 + 2 MnSO4 + 6 K2SO4 + 8 H2O
KHCO3 + Ba(OH)2 = KOH + Ba(HCO3)2 =>
2 KHCO3 + Ba(OH)2 = 2 KOH + Ba(HCO3)2
H2SO4 + Sr(ClO4)2 = SrSO4 + HClO4 =>
H2SO4 + Sr(ClO4)2 = SrSO4 + 2 HClO4
KMnO4 + H2SO4 + Br2 = MnSO4 + KBrO3 + H2O =>
2 KMnO4 + 2 H2SO4 + Br2 = 2 MnSO4 + 2 KBrO3 + 2 H2O
BaSO4 + Pb(NO3)2 = Ba(NO3)2 + Pb(SO4) =>
BaSO4 + Pb(NO3)2 = Ba(NO3)2 + Pb(SO4)
LiOH + (NH4)2CO3 = LiCO3 + (NH4)2OH =>
LiOH + (NH4)2CO3 = LiCO3 + (NH4)2OH
Fe3C + HCl = FeCl2 + CH4 + H2 =>
Fe3C + 6 HCl = 3 FeCl2 + CH4 + H2
Ba + (PO4) = Ba3(PO4)2 =>
3 Ba + 2(PO4) = Ba3(PO4)2
FeO + CH3COOH = (CH3COO)2Fe + H2O =>
FeO + 2 CH3COOH = (CH3COO)2Fe + H2O
Ti(OCH(CH3)2)4 + H2O = Ti(OH)4 + OHCH(CH3)2 =>
Ti(OCH(CH3)2)4 + 4 H2O = Ti(OH)4 + 4 OHCH(CH3)2
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O =>
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
Cr2O7 + NH4{+} + H3O{+} = Cr{3+} + NO3{-} + H2O =>
Cr2O7 + NH4{+} + 4 H3O{+} = 2 Cr{3+} + NO3{-} + 8 H2O
HC2H3O2(aq) + Ba(OH)2(aq) = H2O(l) + Ba(C2H3O2)2(aq) =>
2 HC2H3O2(aq) + Ba(OH)2(aq) = 2 H2O(l) + Ba(C2H3O2)2(aq)
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O =>
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O
LiBr + NaOH = LiOH + NaBr =>
LiBr + NaOH = LiOH + NaBr
KMnO4 + H2SO4 + Br2 = MnSO4 + KBrO3 + H2O =>
2 KMnO4 + 2 H2SO4 + Br2 = 2 MnSO4 + 2 KBrO3 + 2 H2O
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O =>
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O =>
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O
Na2S2O3 + I2 + NaOH = NaI + Na2SO4 + H2O =>
Na2S2O3 + 4 I2 + 10 NaOH = 8 NaI + 2 Na2SO4 + 5 H2O
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
Se + H2 = SeH2 =>
Se + H2 = SeH2
O + H2O + P = H3PO4 =>
5 O + 3 H2O + 2 P = 2 H3PO4
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
MgO2 + Al = AlO2 + Mg =>
MgO2 + Al = AlO2 + Mg
MgPO4 + KOH = MgOH + KPO4 =>
MgPO4 + KOH = MgOH + KPO4
C2H3O2H + KMnO4 + H2SO4 = CO2 + K2SO4 + MnSO4 + H2O =>
5 C2H3O2H + 8 KMnO4 + 12 H2SO4 = 10 CO2 + 4 K2SO4 + 8 MnSO4 + 22 H2O
KMnO4(s) + Na2SO3(s) + H2O(l) = MnO2(s) + Na2SO4(s) + KOH(aq) =>
2 KMnO4(s) + 3 Na2SO3(s) + H2O(l) = 2 MnO2(s) + 3 Na2SO4(s) + 2 KOH(aq)
Au(s) + HNO3(aq) + HCl(aq) = HAuCl4(aq) + NO(g) + H2O(l) =>
Au(s) + HNO3(aq) + 4 HCl(aq) = HAuCl4(aq) + NO(g) + 2 H2O(l)
NaCl + S2 = Na2S + Cl =>
4 NaCl + S2 = 2 Na2S + 4 Cl
CrI3 + H2O2 = CrO4{2-} + IO4{-} + H2O + H{+} =>
2 CrI3 + 27 H2O2 = 2 CrO4{2-} + 6 IO4{-} + 22 H2O + 10 H{+}
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O =>
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O
Na2CO3(aq) + Cu(NO3)2(aq) = Na(NO3) + Cu(CO3) =>
Na2CO3(aq) + Cu(NO3)2(aq) = 2 Na(NO3) + Cu(CO3)
PbBr2 + KBr = KPb + Br =>
PbBr2 + KBr = KPb + 3 Br
Na2HPO4 + BaCl2 = Ba3(PO4)2 + NaCl + HCl =>
2 Na2HPO4 + 3 BaCl2 = Ba3(PO4)2 + 4 NaCl + 2 HCl
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O =>
Ba(OH)2 + KHCO3 = BaCO3 + KOH + H2O
Ag(NO)3 + Na(PO)4 = Ag(PO)4 + Na(NO)3 =>
Ag(NO)3 + Na(PO)4 = Ag(PO)4 + Na(NO)3
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
NaAl(OH)2CO3 + HCl = NaCl + AlCl3 + H2O + CO2 =>
NaAl(OH)2CO3 + 4 HCl = NaCl + AlCl3 + 3 H2O + CO2
KMnO4 + H2SO4 + Br2 = MnSO4 + KBrO3 + H2O =>
2 KMnO4 + 2 H2SO4 + Br2 = 2 MnSO4 + 2 KBrO3 + 2 H2O
NaOH + Cl2 = NaClO3 + NaCl + H2O =>
6 NaOH + 3 Cl2 = NaClO3 + 5 NaCl + 3 H2O
KMnO4 + H2SO4 + Br2 = MnSO4 + KBrO3 + H2O =>
2 KMnO4 + 2 H2SO4 + Br2 = 2 MnSO4 + 2 KBrO3 + 2 H2O
Mn + N2 = MnN =>
2 Mn + N2 = 2 MnN
C19H20O3NF + O2 = CO2 + H2O + N2 + F2 =>
2 C19H20O3NF + 45 O2 = 38 CO2 + 20 H2O + N2 + F2
KOH + CH3COONH4 = CH3COOK + NH3 + H2O =>
KOH + CH3COONH4 = CH3COOK + NH3 + H2O
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Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/28/23
Equations balanced on 01/27/23
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