Equations balanced on the previous day | Equations balanced on the next day |
3 P2O7H4 + 4 Al(OH)3 = Al4(P2O7)3 + 12 H2O
Ba + Ca(NO3)2 = Ca + Ba(NO3) =>
2 Ba + Ca(NO3)2 = Ca + 2 Ba(NO3)
NaCl + Al = AlCl3 + Na =>
3 NaCl + Al = AlCl3 + 3 Na
P2O7H4 + Al(OH)3 = Al4(P2O7)3 + H2O =>
3 P2O7H4 + 4 Al(OH)3 = Al4(P2O7)3 + 12 H2O
MnO2 + Al = Al2O3 + Mn =>
3 MnO2 + 4 Al = 2 Al2O3 + 3 Mn
Sn4O + MgCl = Sn4Cl + MgO =>
Sn4O + MgCl = Sn4Cl + MgO
MnO2 + RbOH + H2O = Rb2[Mn(OH)6] =>
MnO2 + 2 RbOH + 2 H2O = Rb2[Mn(OH)6]
P2O7H4 + Al(OH)3 = Al4(P2O7)3 + H2O =>
3 P2O7H4 + 4 Al(OH)3 = Al4(P2O7)3 + 12 H2O
MnO2 + RbOH + H2O = Rb2[Mn(OH)6] =>
MnO2 + 2 RbOH + 2 H2O = Rb2[Mn(OH)6]
CH3COOH + CaCO3 = CHCOOHCa + H2CO3 =>
CH3COOH + CaCO3 = CHCOOHCa + H2CO3
Fe{2+} + Bi03{-} = Fe04{-} + Bi{3+} =>
40 Fe{2+} + 9 Bi03{-} = 10 Fe04{-} + 27 Bi{3+}
MnO2 + RbOH + H2O = Rb2[Mn(OH)6] =>
MnO2 + 2 RbOH + 2 H2O = Rb2[Mn(OH)6]
C12H24 + C8H18 + Na2SO4 = C20H42O4 + Na2S =>
C12H24 + C8H18 + Na2SO4 = C20H42O4 + Na2S
MnO2 + RbOH + H2O = Rb2[Mn(OH)6] =>
MnO2 + 2 RbOH + 2 H2O = Rb2[Mn(OH)6]
Fe{2+} + Bi03{-} = Fe04{-} + Bi{3+} =>
40 Fe{2+} + 9 Bi03{-} = 10 Fe04{-} + 27 Bi{3+}
CaI2 + AlBr3 = AlI3 + CaBr2 =>
3 CaI2 + 2 AlBr3 = 2 AlI3 + 3 CaBr2
K + H2O = KOH + H2 =>
2 K + 2 H2O = 2 KOH + H2
MnO2 + RbOH + H2O = Rb2[Mn(OH)6] =>
MnO2 + 2 RbOH + 2 H2O = Rb2[Mn(OH)6]
NH3 + AgNO3 = NNO3 + H3Ag =>
NH3 + AgNO3 = NNO3 + H3Ag
NaCl + H3PO4 = HCl + Na3PO4 =>
3 NaCl + H3PO4 = 3 HCl + Na3PO4
P2O7H4 + Al(OH)3 = Al4(P2O7)3 + H2O =>
3 P2O7H4 + 4 Al(OH)3 = Al4(P2O7)3 + 12 H2O
P2O7H4 + Al(OH)3 = Al4(P2O7)3 + H2O =>
3 P2O7H4 + 4 Al(OH)3 = Al4(P2O7)3 + 12 H2O
Hg + HNO3 = Hg2(NO3)2 + NO + H2O =>
6 Hg + 8 HNO3 = 3 Hg2(NO3)2 + 2 NO + 4 H2O
Bi + HCl + O2 = BiCl3 + H2O =>
4 Bi + 12 HCl + 3 O2 = 4 BiCl3 + 6 H2O
Fe{2+} + Bi03{-} = Fe04{-} + Bi{3+} =>
40 Fe{2+} + 9 Bi03{-} = 10 Fe04{-} + 27 Bi{3+}
SnCl2 + SO2 + H3 = SnCl4 + SnS2 + H2O =>
6 SnCl2 + 6 SO2 + 8 H3 = 3 SnCl4 + 3 SnS2 + 12 H2O
{-} = {-}53 =>
e = {-}53
Fe + H3CCH2Cl + H2O = FeCl2 + CH3CH2OH + H2 =>
Fe + 2 H3CCH2Cl + 2 H2O = FeCl2 + 2 CH3CH2OH + H2
K2Cr2O7 + HCl = KCl + CrCl3 + H2O + Cl2 =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 7 H2O + 3 Cl2
Fe(CO)5 + NaOH = Na2Fe(CO)4 + Na2CO3 + H2O =>
Fe(CO)5 + 4 NaOH = Na2Fe(CO)4 + Na2CO3 + 2 H2O
Fe{2+} + Bi03{-} = Fe04{-} + Bi{3+} =>
40 Fe{2+} + 9 Bi03{-} = 10 Fe04{-} + 27 Bi{3+}
P2O7H4 + Al(OH)3 = Al4(P2O7)3 + H2O =>
3 P2O7H4 + 4 Al(OH)3 = Al4(P2O7)3 + 12 H2O
Mg + Br = MgBr2 =>
Mg + 2 Br = MgBr2
CH3CH2COOH + Cu(OH)2 = Cu2O + CO2 + H2O =>
CH3CH2COOH + 14 Cu(OH)2 = 7 Cu2O + 3 CO2 + 17 H2O
NaI + NaHSO4 + HCl = I2 + SO2 + NaCl + H2O =>
2 NaI + NaHSO4 + 3 HCl = I2 + SO2 + 3 NaCl + 2 H2O
Ca + Br = Br2Ca =>
Ca + 2 Br = Br2Ca
MnO2 + RbOH + H2O = Rb2[Mn(OH)6] =>
MnO2 + 2 RbOH + 2 H2O = Rb2[Mn(OH)6]
Fe{2+} + Bi03{-} = Fe04{-} + Bi{3+} =>
40 Fe{2+} + 9 Bi03{-} = 10 Fe04{-} + 27 Bi{3+}
P2O7H4 + Al(OH)3 = Al4(P2O7)3 + H2O =>
3 P2O7H4 + 4 Al(OH)3 = Al4(P2O7)3 + 12 H2O
C5O2H8 + O2 = H2O + COH =>
4 C5O2H8 + 9 O2 = 6 H2O + 20 COH
Ba(NO2)2 + H2 = BaO + N2O + H2O =>
Ba(NO2)2 + 2 H2 = BaO + N2O + 2 H2O
C3H5OH + H2O2 = C3H5(OH)3 =>
C3H5OH + H2O2 = C3H5(OH)3
Cl(aq) + NaBr(aq) = Br2(l) + NaCl(aq) =>
2 Cl(aq) + 2 NaBr(aq) = Br2(l) + 2 NaCl(aq)
Fe{2+} + Bi03{-} = Fe04{-} + Bi{3+} =>
40 Fe{2+} + 9 Bi03{-} = 10 Fe04{-} + 27 Bi{3+}
K2MnO4 + KOH = H2O + K3MnO4 + O2 =>
4 K2MnO4 + 4 KOH = 2 H2O + 4 K3MnO4 + O2
H2CO3 + Pb(OH)4 = PbCO4 + H2O =>
H2CO3 + Pb(OH)4 = PbCO4 + 3 H2O
SO3 + Fe2O3 = Fe2SO3 + O2 =>
2 SO3 + 2 Fe2O3 = 2 Fe2SO3 + 3 O2
CuO + Al(OH)3 = Cu(OH)2 + Al + O =>
3 CuO + 2 Al(OH)3 = 3 Cu(OH)2 + 2 Al + 3 O
NaNO3 + CH3COOH + KCl = NaNO2 + CH3COOK + H2O + Cl2 =>
NaNO3 + 2 CH3COOH + 2 KCl = NaNO2 + 2 CH3COOK + H2O + Cl2
KIO3(s) = KI + O2 =>
2 KIO3(s) = 2 KI + 3 O2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/28/23
Equations balanced on 01/27/23
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